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3 years ago

Triangle ABC is an equilateral triangle with side lengths labeled a, b, and c.

Mathematics

2 answers:

Butoxors [25]3 years ago

6 0

Answer:

the answers are all bold below

Step-by-step explanation:

Triangle ABC is an equilateral triangle with side lengths labeled a, b, and c.

Triangle A B C is an equilateral triangle. The length of side A B is c, the length of B C is a, and the length of A C is b.

Trigonometric area formula: Area = One-half a b sine (C)

Which expressions represent the area of triangle ABC? Select three options.

a c sine (60 degrees)

One-half b c sine (60 degrees)

One-half a squared sine (60 degrees)

StartFraction a squared b sine (60 degrees) Over 2 EndFraction

StartFraction a b sine (60 degrees) Over 2 EndFraction

alina1380 [7]3 years ago

3 0

Answer:

B C E

Step-by-step explanation:

I took the test

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Juliette [100K]

Answer:

50% of 1/3: 1/2 x 1/3 = 1/6

75% of 1/2: 3/4 x 1/2 = 3/8

Step-by-step explanation:

50% = 1/2

50% of 1/3: 1/2 x 1/3 = 1/6

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3 years ago

Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

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