All categories

2 years ago

Triangle ABC is an equilateral triangle with side lengths labeled a, b, and c.

Mathematics

2 answers:

Butoxors [25]2 years ago

6 0

Answer:

the answers are all bold below

Step-by-step explanation:

Triangle ABC is an equilateral triangle with side lengths labeled a, b, and c.

Triangle A B C is an equilateral triangle. The length of side A B is c, the length of B C is a, and the length of A C is b.

Trigonometric area formula: Area = One-half a b sine (C)

Which expressions represent the area of triangle ABC? Select three options.

a c sine (60 degrees)

One-half b c sine (60 degrees)

One-half a squared sine (60 degrees)

StartFraction a squared b sine (60 degrees) Over 2 EndFraction

StartFraction a b sine (60 degrees) Over 2 EndFraction

alina1380 [7]2 years ago

3 0

Answer:

B C E

Step-by-step explanation:

I took the test

You might be interested in

PLs help me with this problem.

allsm [11]

He will need 127 bags

3 0

2 years ago

Read 2 more answers

Daniel wanted to know his approximate score on the final exam for his mathematics class. His professor hinted that his score was

Marizza181 [45]

Answer:

The raw score for his exam grade is 99.69.

Step-by-step explanation:

Given : The professor announced that the mean for the class final exam was 88 with a standard deviation of 7. Given Daniel's z score of 1.67.

To find : What is the raw score for his exam grade?

Solution :

The formula use to find the z-score is

$z=\dfrac{x-\mu}{\sigma}$

Where, z=1.67 is the z-score

$\mu=88$ is the means

$\sigma=7$ is the standard deviation

x is the raw score for his exam grade

Substitute the values,

$1.67=\dfrac{x-88}{7}$

$1.67\times 7=x-88$

$11.69=x-88$

$x=88+11.69$

$x=99.69$

Therefore, the raw score for his exam grade is 99.69.

7 0

2 years ago

A cell site is a site where electronic communications equipment is placed in a cellular network for the use of mobile phones. Th

Olegator [25]

Answer:

(a) 74553

(b) 172120

Step-by-step explanation:

Given

$y = \frac{340110}{1 + 377e^{-0.259t}}$

Solving (a): 1998

Year 1998 means that:

$t =1998 - 1980$

$t =18$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*18}}$

$y = \frac{340110}{1 + 377e^{-4.662}}$

$y = \frac{340110}{1 + 3.562}$

$y = \frac{340110}{4.562}$

$y = 74553$ --- approximated

Solving (b): 2003

Year 2003 means that:

$t = 2003 - 1980$

$t =23$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*23}}$

$y = \frac{340110}{1 + 377e^{-5.957}}$

$y = \frac{340110}{1 + 0.976}$

$y = \frac{340110}{1.976}$

$y = 172120$ --- approximated

Solving (c): 2006

Year 2006 means that:

$t = 2006 - 1980$

$t =26$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*26}}$

$y = \frac{340110}{1 + 377e^{-6.734}}$

$y = \frac{340110}{1 + 0.4485}$

$y = \frac{340110}{1.4485}$

$y = 234802$ --- approximated

3 0

2 years ago

Every workday, Zoe bikes 2.6 miles to work along city streets. On the way back, she likes to take a shortcut through a park, so

snow_lady [41]

Answer:

I'm pretty sure it's 7.1 miles in a week

8 0

2 years ago

Read 2 more answers

HELPPPPPP

SOVA2 [1]

Answer:

10^-99

10^-17

10^-5

10⁵

10¹⁴

10³⁰

8 0

2 years ago