(2-c,y) is the answer for the problem.
Find the area of each shape and add.Let's start with the first semi-circle(half-circle)
If the area of a circle is πr² , then the area of a semi-circle is 1/2πr² where is 22/7 or 3.14, and r is the radius which is 1.8 meters
A=1/2πr²
A=1/2*22/7*1.8*1.8
A=5.09 m²(rounded to nearest hundredth)
Since the semi-circles are two and have the same radius, multiply the area of the first one by two or go through the same process again.
So 5.09 *2=10.18meters square is the area of the two semi-circles
Now, let's find the area of a rectangle which is length times width, where length is 6 meters and width is (1.8+1.8, because 1.8 is half the width)=3.6 meters
A=l*w
A=6*3.6
A=21.6meters square
Therefore the area of the shape is 10.18m²+21.6m²=219.888m²
<em>To get all possible permutations of these five spaces, we just multiply these numbers (that is, 8∗7∗6∗5∗4=6,720)</em>
<em>There are 6,720 five digit numbers that can be formed from the digits provided given that no digit may be repeated.</em>
<em>Hope that helped!</em>
Answer:
x = -13
Step-by-step explanation:
6(4x + 50) = 3(x+8) + 3
24x + 300 = 3x + 24 + 3
21x + 300 = 27
21x = -273
x = -13
