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slavikrds [6]
3 years ago
7

There are eight performers who will present their comedy acts this weekend at a comedy club. How many different ways are there t

o schedule their appearances?
Mathematics
1 answer:
svet-max [94.6K]3 years ago
8 0
Since there is no restriction as to the order of the performers, I think that the answer to this problem is just the factorial of 8. So 8! is equal to (8)(7)(6)(5)(4)(3)(2)(1) which in turn is equal to 40,320 times. There are 40,320 different ways to schedule the appearances of the eight performers.
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Triangle RST has vertices located at R (2, 3), S (4, 4), and T (5, 0).
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The length of the sides are 2.24, 4.24 and 4.12 units while the slope are 0.5, -1 and -4.

<h3>Linear equation</h3>

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial value of y.

For RS:

  • Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(4-3)^2+(4-2)^2}=2.24   \\&#10;\\&#10;slope=\frac{y_2-y_1}{x_2-x_1} =\frac{4-3}{4-2}=0.5

For RT:

  • Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(0-3)^2+(5-2)^2}=4.24   \\&#10;\\&#10;slope=\frac{y_2-y_1}{x_2-x_1} =\frac{0-3}{5-2}=-1

For ST:

  • Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(0-4)^2+(5-4)^2}=4.12   \\&#10;\\&#10;slope=\frac{y_2-y_1}{x_2-x_1} =\frac{0-4}{5-4}=-4

The length of the sides are 2.24, 4.24 and 4.12 units while the slope are 0.5, -1 and -4.

Find out more on linear equation at: brainly.com/question/14323743

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