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3 years ago

Find me midpoint of -9 and 6

Mathematics

2 answers:

Ymorist [56]3 years ago

4 0

The answer I believe is -2. Thank you come again

Alexandra [31]3 years ago

4 0

Answer:

-3/2 or -1.5

Step-by-step explanation:

1) Write out the numbers:

-9, -8, -7, -6, -5, -4, -3, [-2, -1] 0, 1 , 2, 3, 4, 5, 6

2)-2 and -1 are in the middle

3)Add the numbers in the middle and divide by 2

Add the 2 numbers: (-2)+(-1)=-3

Divide by 2: -3/2
Answer: -1.5

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3 years ago

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Step-by-step explanation:

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3 years ago

Domain and Range for the function f(x)=5IXI is

shutvik [7]

Answer:

The domain of the function f(x) is:

$\mathrm{Domain\:of\:}\:5\left|x\right|\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

The range of the function f(x) is:

$\mathrm{Range\:of\:}5\left|x\right|:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

Step-by-step explanation:

Given the function

$f\left(x\right)=5\left|x\right|$

Determining the domain:

We know that the domain of the function is the set of input or arguments for which the function is real and defined.

In other words,

Domain refers to all the possible sets of input values on the x-axis.

It is clear that the function has undefined points nor domain constraints.

Thus, the domain of the function f(x) is:

$\mathrm{Domain\:of\:}\:5\left|x\right|\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

Determining the range:

We also know that range is the set of values of the dependent variable for which a function is defined.

In other words,

Range refers to all the possible sets of output values on the y-axis.

We know that the range of an Absolute function is of the form

$c|ax+b|+k\:\mathrm{is}\:\:f\left(x\right)\ge \:k$

$k=0$

Thus, the range of the function f(x) is:

$\mathrm{Range\:of\:}5\left|x\right|:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

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3 years ago

Find all real and imaginary solutions to the equation x^3-4x^2+x-4=0

lawyer [7]

Step-by-step explanation:

STEP 1

Equation at the end of step 1

(((x3) - 22x2) + x) - 4 = 0

STEP 2

Checking for a perfect cube

2.1 x3-4x2+x-4 is not a perfect cube

5 0

3 years ago

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pantera1 [17]

Answer:

(`n*0.05)+(d*0.10)<2

Step-by-step explanation:

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