there are 16 ounces in a pound so 16x7=112 +2= 114
Answer:
D. (2,1)
Step-by-step explanation:
Fill in the value for y from the first eq (6x-11) into the second:
-2x - 3(6x-11) = -7
Now simplify:
-2x -18x + 33 = -7
-20x = -7-33
20x = 40
x = 2
Now that we have x, plug it into the top eq to get y:
y = 6*2 - 11 = 1
Et voila, x=2 and y=1, so the solution is (2,1).
Answer:
-27,-32,-37,-42,-47
Step-by-step explanation:
Answer:
15
Step-by-step explanation:
So, leets look at the graph.
We can see that the lines being solved for tecnically make up 180 degrees.
This is because the value of the angles on line m are equal to the value of the angles on line n.
So, we know that the total line, 180 degrees, is 7x-10, and 6x-5.
Lets combine these two equations, and subtract them from 180 degrees to solve for x:
7x-1+6x-5
=
13x-15
Now to solve for x:
13x-15=180
Add 15 to both sides to get 13x alone:
13x=195
Then divide both sides by 13 to get x alone:
x=15
So our value of x is 15!
Hope this helps! :)
Answer:
2. D. 
1. C. 
Step-by-step explanation:
![\displaystyle 2A_B + h[c + b + a] = S.A.](https://tex.z-dn.net/?f=%5Cdisplaystyle%202A_B%20%2B%20h%5Bc%20%2B%20b%20%2B%20a%5D%20%3D%20S.A.)
Area of a <em>Triangle</em> [keep this in mind to find the base area]:
Pythagorean Theorem [You will need this theorem to find the lengths of both hypotenuses on both triangular bases]:
2. ![\displaystyle 2A_B + p[c + 3 + 4] = 120 → 2[6] + p[5 + 3 + 4] = 120 \\ \\ 12 + 12p = 120 → 108 = 12p; 9 = p](https://tex.z-dn.net/?f=%5Cdisplaystyle%202A_B%20%2B%20p%5Bc%20%2B%203%20%2B%204%5D%20%3D%20120%20%E2%86%92%202%5B6%5D%20%2B%20p%5B5%20%2B%203%20%2B%204%5D%20%3D%20120%20%5C%5C%20%5C%5C%2012%20%2B%2012p%20%3D%20120%20%E2%86%92%20108%20%3D%2012p%3B%209%20%3D%20p)
1. ![\displaystyle 2A_B + 15[c + 6 + 8] = S.A. → 2[24] + 15[10 + 6 + 8] = S.A. \\ \\ 48 + 15[24] = S.A. → 48 + 360 = S.A.; 408 = S.A.](https://tex.z-dn.net/?f=%5Cdisplaystyle%202A_B%20%2B%2015%5Bc%20%2B%206%20%2B%208%5D%20%3D%20S.A.%20%E2%86%92%202%5B24%5D%20%2B%2015%5B10%20%2B%206%20%2B%208%5D%20%3D%20S.A.%20%5C%5C%20%5C%5C%2048%20%2B%2015%5B24%5D%20%3D%20S.A.%20%E2%86%92%2048%20%2B%20360%20%3D%20S.A.%3B%20408%20%3D%20S.A.)
I am delighted to assist you anytime.
