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andrew11 [14]
3 years ago
15

A rectangular lawn is 65 m long and 34 m wide. Over time, people have walked along a diagonal as a shortcut and have created a s

traight path. What is the length of the path, to the nearest tenth of a meter? Enter your answer as a deicmal in the box.
Mathematics
2 answers:
CaHeK987 [17]3 years ago
5 0

Answer:

73.4

Step-by-step explanation:

I am simply confirming that this answer is the correct solution. :D

irina [24]3 years ago
3 0
To calculate the length of the diagonal, use the Pythagorean theorem:
c^2 = a^2 + b^2, where c is the diagonal.
c^2 = 65^2 + 34^2
c^2 = 4225 + 1156
c^2 = 5381
c ~ 73.36
To the nearest tenth of a meter, the diagonal has a length of 73.4 m
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50 points :] !!
nasty-shy [4]

Given,

LP = 15, PR = 9

Point P lies on the line segment PR. It would mean that,

LP + PR = LR

⇒LR = 15 + 9

⇒ LR = 24

Hence, "LR = 24 because LP + PR = LR according to the Segment Addition Postulate, and 15 + 9 = 24 using substitution" is the correct option.

6 0
3 years ago
Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. Th
Verizon [17]

Answer:

(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422

(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778

And we are 95% confident that the true difference means are between 1.422 \leq \mu_1 -\mu_2 \leq 2.778

Step-by-step explanation:

We know the following info:

\bar X_1 = 21.9 sample mean for group 1

\bar X_2 = 19.8 sample mean for group 2

s_1 = 3.4 sample standard deviation for group 1

s_2 = 3.5 sample standard deviation for group 2

n_1 = 200 sample size group 1

n_2 = 200 sample size group 2

We want to find a confidence interval for the difference of means and the correct formula to do this is:

(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}

Now we just need to find the critical value. The confidence level is 0.95 then the significance is 1-0.95 =0.05 and \alpha/2 =0.025. The degrees of freedom are given by:

df= n_1 +n_2 -2= 200+200-2= 398

The critical value for this case would be :t_{\alpha/2}=1.966  

And replacing into the confidence interval formula we got:

(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422

(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778

And we are 95% confident that the true difference means are between 1.422 \leq \mu_1 -\mu_2 \leq 2.778

5 0
3 years ago
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goldfiish [28.3K]

Answer:

here's your answer tho: ∞

Step-by-step explanation:

3 0
3 years ago
10 POINTS!.A sculptor is planning to make two triangular prisms out of steel. The sculptor will use △ABC for the bases of one pr
gizmo_the_mogwai [7]

Answer:

if they are similar then their sides are proportional and the following would be true:  

40/30 = 48/36  

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Step-by-step explanation:

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Finding the Equation of a Line from a Graph and a Table <br><br> plz help me
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Answer:

slope (m)= 1/2

y-intercept: (0, -1)

equation: y=\frac{1}{2}x-1

Step-by-step explanation:

slope is \frac{rise}{run\\}=\frac{1}{2}

y-intercept is where the line crosses the vertical axis (y-axis) so its (0, -1)

using point slope form:

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y-(-1)=1/2(x-0)

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