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TiliK225 [7]
3 years ago
12

Which figures have only one pair of parallel lines

Mathematics
1 answer:
nordsb [41]3 years ago
3 0

Answer:

It is a trapezoid

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P and Q are similar hexagonal pyramids. The scale factor of P to Q is 6 : 1. If the volume of Q is 8 cubic yards, find the volum
tatiyna

Answer:

The volume of P is <u>1728 cubic yards.</u>

<u></u>

Step-by-step explanation:

For similar shapes, the ratio of volumes are defined as:

\frac{V_{1} }{V_{2}} = (\frac{h_{1} }{h_{2}}) ^{3}

where h1 and h2 are the heights of each pyramid respectively.

We know that the scale factor of P to Q is 6:1 i.e. the ratio of heights is also 6:1. And the volume of Q is given as 8 cubic yards. so, using the relation defined above we can write:

\frac{V_{P} }{V_{Q}} = (\frac{h_{P} }{h_{Q}}) ^{3}

\frac{V_{P} }{8} = (\frac{6}{1} )^{3}

Vp = 6³ * 8

     = 216 * 8

Vp = 1728 cubic yards

The volume of P is <u>1728 cubic yards.</u>

8 0
3 years ago
3 2/5x1/2 help find the answer asap
babunello [35]

Answer

1 7/10

Step-by-step explanation:

(3 2/5)(1/2)=17/5=1 7/10



5 0
3 years ago
How many terms are in this expression? <br> s+3u+10=
Stella [2.4K]
There are 3 terms in this expression s, 3u, and 10
3 0
3 years ago
Evaluate the cosine angle X please !
sveta [45]

Answer:

in right angled triangle

h =√(24²+7²)=25

cos X = base/hypotenuse=24/25

5 0
3 years ago
Please help and solve for each will give brainliest
sergiy2304 [10]
Comment
The measurement of an arc in degrees is the same as the central angle. We must assume that the central angle is the measurement given. 
\overset{\LARGE{\frown}}{AB} = 49

To find the next one you need to find the measurement from B to C, the arc that is over 180 degrees. Maybe you could put another letter between B and C so that we could refer to that top arc greater than 180 degrees. Call the point you inserted  D. 

\overset{\LARGE{\frown}}{BDC} = 360 - 49 - 107 = 204
\overset{\LARGE{\frown}}{ABC} = \overset{\LARGE{\frown}}{BDC} + \overset{\LARGE{\frown}}{AB} 

Arc(ABC) = 204 + 49 = 253

Arc(BAC) = Arc(BC) + Arc(AB)
Arc(BAC) = 107 + 49
Arc(BAC) = 156

Arc(ACB) = 107 + 204 = 311   


 

5 0
3 years ago
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