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igor_vitrenko [27]
3 years ago
11

-3[1+2(4+5)] PLease answer ASAP!!!

Mathematics
2 answers:
MAVERICK [17]3 years ago
5 0

Answer:

-57

Step-by-step explanation:

To solve this problem, you need to use the acronym PEMDAS.

P = parenthesis (if there is any in the expression) or brackets

E = exponents (if there is any in the expression)

D/M = Divide or Multiply or both

A/S = Add or Subtract or both

In the problem, you need to simplify the parentheses ( ) inside the brackets first. For example: -3 [1 + 2<u>(4 + 5)</u>]. That will equal to -3 [1 + 2<u>(9)</u>]. Next, you can solve the brackets now. Since there is both a addition and multiplication problem inside these brackets, you must do the multiplying first. For example,

-3 [1 + <u>2(9)</u>]. That equals to -3 [ 1 + 18}. Next, do the addition inside of the brackets and then multiply that answer to -3. For example, -3 [<u>1 + 18</u>}. That equals to -3 [19]. Do the multiplication by a calculator or by hand. if you are doing by hand, ignore the signs of the numbers until the very end.

If doing by hand, first you need to multiply 9 by the 3 to get 27. Keep the 7 and borrow a 2 on top of the ones places which is 1. Multiply the 1 by the 3 which gets 3 and add 2 to the 3 to get 5. You got the 2 from multiplying 9 by 3 which is 27. Since the 3 in this problem is negative, that will leave your answer with a negative number. Since a negative times a postive will always be negative. If the number of negatives is odd in the problem, then it will a negative answer. If the number of negatives is even, the answer will be positive. Same thing applies to division. You get -57 as your answer.

19

<u>× 3</u>

vaieri [72.5K]3 years ago
4 0

Answer:

-57

Step-by-step explanation:

<h2><u>Use BOMAS</u></h2>

B- brackets

O- of

M- multiplication

A- addition

S - subtraction

-3[1+2(4+5)]

first solve what is in the brackets

(4+5) = 9

place 9 in the brackets

-3[1+2(9)]

now multiply the 2 and 9

2*9 = 18

-3[1+18)]

1+ 18 = 19

now multiply the (-3) with 19

= <u>-57</u>

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\qquad\qquad\huge\underline{{\sf Answer}}♨

Let's solve ~

\qquad \sf  \dashrightarrow \:40 + x + 25 = 180

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