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3 years ago

Find the area of the shaded portion. Please? I´ll mark Branliest!

Mathematics

2 answers:

umka21 [38]3 years ago

8 0

Answer:

53.86 cm using 3.14 as pi.

Step-by-step explanation:

Hope this helps!

hodyreva [135]3 years ago

8 0

Answer:

53.94

if you do the area of the circle then subtract 100 from the answer

Step-by-step explanation:

hope this is okay

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An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 35, de

Amiraneli [1.4K]

Answer:

a) P=0.1721

b) P=0.3528

c) P=0.3981

Step-by-step explanation:

This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

a) In this case we have a sample size of n=15.

The value of p is p=25/(25+35)=0.4167 and q=1-0.4167=0.5833.

The probability of having exactly 10 projects for the second section is equal to having exactly 5 projects of the first section.

This probability can be calculated as:

$P=\frac{n!}{(n-k)!k!}p^kq^{n-k}= \frac{15!}{(10)!5!}\cdot 0.4167^5\cdot0.5833^{10}=0.1721$

b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

We apply the same formula but as a sum:

$P(k\leq5)=\sum_{k=0}^{5}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have:

$P(k=0)=0.0003\\P(k=1)=0.0033\\P(k=2)=0.0165\\P(k=3)=0.0511\\P(k=4)=0.1095\\P(k=5)=0.1721\\\\P(k\leq5)=0.0003+0.0033+0.0165+0.0511+0.1095+0.1721=0.3528$

c) In this case, we have the sum of the probability that k is equal or less than 5, and the probability tha k is 10 or more (10 or more projects belonging to the 1st section).

The first (k less or equal to 5) is already calculated.

We have to calculate for k equal to 10 or more.

$P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have

$P(k=10)=0.0320\\P(k=11)=0.0104\\P(k=12)=0.0025\\P(k=13)=0.0004\\P(k=14)=0.0000\\P(k=15)=0.0000\\\\P(k\geq10)=0.032+0.0104+0.0025+0.0004+0+0=0.0453$

The sum of the probabilities is

$P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981$

8 0

3 years ago

A line passes through the point (4, –6) and has a slope of Negative three-fourths. Which is the equation of the line?

marissa [1.9K]

Answer:

y = -3/4x - 3

Step-by-step explanation:

...................

8 0

3 years ago

Ms. Sublett's math class is putting three

givi [52]

Option 4 is your answer

4 0

2 years ago

Can someone help me with this? Preferably with an explanation on how to actually figure this out. Thank you!

zhannawk [14.2K]

Answer:

2^-4, 1/16, (1/2)^4

There is a rule with exponents, if you are dividing two exponents you subtract the first exponent from the other to simplify it, also meaning it's equivalent.

So in this case 5-9 = 2^-4

The others were found by evaluation.

5 0

2 years ago

Twice the sum of a number and 11 is 34.

Maru [420]

Answer:

The number is 6.

Solution:

2(x + 11) = 34
=> 2x + 22 = 34
=> 2x = 34 - 22
=> 2x = 12
=> x = 12/2
=> x = 6

Hence, the number is 6.

$BrainiacUser1357$

7 0

2 years ago