Please helppppp !!!!!!!

Suppose that the data for analysis includes the attributeage. Theagevalues for the datatuples are (in increasing order) 13, 15,

Bas_tet [7]

Answer:

a) $\bar X = \frac{\sum_{i=1}^{27} X_i }{27}= \frac{809}{27}=29.96$

$Median = 25$

b) $Mode = 25, 35$

Since 25 and 35 are repeated 4 times, so then the distribution would be bimodal.

c) $Midrange = \frac{70+13}{3}=41.5$

d) $Q_1 = \frac{20+21}{2} =20.5$

$Q_3 =\frac{35+35}{2}=35$

e) Min = 13 , Q1 = 20.5, Median=25, Q3= 35, Max = 70

f) Figura attached.

g) When we use a quantile plot is because we want to show the percentage or the fraction of values below or equal to an specified value for the distribution of the data.

By the other hand the quantile-quantile plot shows the quantiles of the distribution values against other selected distribution (specified, for example the normal distribution). If the points are on a straight line we assume that the data values fit very well to the hypothetical distribution selected.

Step-by-step explanation:

For this case w ehave the following dataset given:

13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70.

Part a

The mean is calculated with the following formula:

$\bar X = \frac{\sum_{i=1}^{27} X_i }{27}= \frac{809}{27}=29.96$

The median on this case since we have 27 observations and that represent an even number would be the 14 position in the dataset ordered and we got:

$Median = 25$

Part b

The mode is the most repeated value on the dataset on this case would be:

$Mode = 25, 35$

Since 25 and 35 are repeated 4 times, so then the distribution would be bimodal.

Part c

The midrange is defined as:

$Midrange = \frac{Max+Min}{2}$

And if we replace we got:

$Midrange = \frac{70+13}{3}=41.5$

Part d

For the first quartile we need to work with the first 14 observations

13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25

And the Q1 would be the average between the position 7 and 8 from these values, and we got:

$Q_1 = \frac{20+21}{2} =20.5$

And for the third quartile Q3 we need to use the last 14 observations:

25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70

And the Q3 would be the average between the position 7 and 8 from these values, and we got:

$Q_3 =\frac{35+35}{2}=35$

Part e

The five number summary for this case are:

Min = 13 , Q1 = 20.5, Median=25, Q3= 35, Max = 70

Part f

For this case we can use the following R code:

> x<-c(13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70)

> boxplot(x,main="boxplot for the Data")

And the result is on the figure attached. We see that the dsitribution seems to be assymetric. Right skewed with the Median<Mean

Part g

When we use a quantile plot is because we want to show the percentage or the fraction of values below or equal to an specified value for the distribution of the data.

By the other hand the quantile-quantile plot shows the quantiles of the distribution values against other selected distribution (specified, for example the normal distribution). If the points are on a straight line we assume that the data values fit very well to the hypothetical distribution selected.

6 0

3 years ago

What is 30 percent of 25

sweet [91]

7.5 is 30 percent of 25 because

25 divided by 10 is 2.5 times 3 is 7.5

6 0

3 years ago

Please help!

mariarad [96]

Answer: 1,045 passengers

Step-by-step explanation:

This question involves multiple steps. Let's first try to figure the number of children on the cruise.

The ratio of girls to the total number of children was 2:5. There are 198 boys.

This information tells me that for every 5 children, there's 2 girls and 3 boys.

Based off of this information, we can divide the total number of boys by 3 in order to find the number of children.

198÷3=66

Let's multiply 66 by 5 since that's the number of groupings based off the ratio.

66×5=330

Let's check the number of children. Since the ratio of girls to total children is 2:5 and we already confirmed there's 198 boys, there should be 132 girls. We can turn this ratio into a fraction where 2/5 of the children are girls. we can confirm this by multiply 330 by 2/5 (0.4) and getting 132.

There are 330 children on the cruise.

The ratio of the number of adults to the number of children was 13:6.

For every 6 children, there were 13 adults. Let's divide the number of children by 6 in order to find the number of groupings.

330÷6=55

Let's now multiply the groupings by 13 to find the number of adults.

55×13=715

So there should be 715 adults and 330 children on the cruise.

715+330=1,045

5 0

3 years ago

A farmers productions statistics finds that it takes 2 chickens to produce 6 eggs in 24 hours. How many chickens will be needed

Lelu [443]

Answer:

8 chickens

Step-by-step explanation:

Firstly, we need to know the number of eggs produced by a single chicken in 24 hours.

Since 2 chickens produce 6 eggs in 24hours, this means 1 chicken will produce 3 eggs in 24 hours.

Now, we need 24 eggs to be produced. Since the time is the same 24hours, meaning time is constant, the number of chickens required to produce 24 eggs will be 24/3 = 8 chickens

Hence, we can say that 8 chickens will produce 24eggs in 24 hours

7 0

3 years ago

the box plot suggests that about 25% of quarterbacks in the boys football league threw fewer than what number of touchdowns?

stiks02 [169]

Answer: the answer is 7

Step-by-step explanation:

7 0

3 years ago