Question

Evaluate 3+jk+k^3 when j=2 and k=6

Answer 1

Answer:

231

Step-by-step explanation:

$3+jk+k^3\\\\j = 2\\k=6\\\\3+ 2(6) + 6^3\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:exponents}\:6^3\::\quad 216\\=3+2\left(6\right)+216\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:2\left(6\right)\::\quad 12\\=3+12+216\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:3+12+216\:\\:\quad 231$

Answer 2

Answer:

$231$

Step-by-step explanation:

$3 + jk + k {}^{3} = 3 + 2(6) + 6 {}^{3} = 3 + 12 + 216 = 231$