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3 years ago

Evaluate 3+jk+k^3 when j=2 and k=6

Mathematics

2 answers:

Lynna [10]3 years ago

5 0

Answer:

Step-by-step explanation:

$3+jk+k^3\\\\j = 2\\k=6\\\\3+ 2(6) + 6^3\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:exponents}\:6^3\::\quad 216\\=3+2\left(6\right)+216\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:2\left(6\right)\::\quad 12\\=3+12+216\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:3+12+216\:\\:\quad 231$

sashaice [31]3 years ago

3 0

Answer:

$231$

Step-by-step explanation:

$3 + jk + k {}^{3} = 3 + 2(6) + 6 {}^{3} = 3 + 12 + 216 = 231$

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<h2>-Answer :</h2>

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<h2><u>Solution</u> :</h2>

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3 years ago

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nirvana33 [79]

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3 years ago

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alina1380 [7]

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Options (A) and (D).

Step-by-step explanation:

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3 years ago