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3 years ago

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A gas in a piston–cylinder assembly undergoes a compression process for which the relation between pressure and volume is given

by pVn = constant. The initial volume is 0.1 m3 , the final volume is 0.04 m3 , and the final pressure is 2 bar. Determine the initial pressure,

1 answer:

hichkok12 [17]3 years ago

3 0

Answer:

???

Explanation:

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A six pack of your favorite beverage (12 fl. oz. cans, assumed to have the same characteristics as water) is placed in a cooler

nasty-shy [4]

Answer:

$Q = 169 BTU$

Explanation:

As we know that volume is given as

$V = 12 Fl oz$

so it is given in liter as

$V = 12 fl oz = 0.355 Ltr$

now we have six pack of such volume

so total volume is given as

$V = 6\times 0.355 Ltr$

$V = 2.13 ltr$

so its mass is given as

$m = 2.13 kg$

now the change in temperature is given as

$\Delta T = 70 - 34 = 36 ^oF$

$\Delta T = 20^oC$

now the heat given to the liquid is given as

$Q = ms\Delta T$

$Q = 2.13(4186)(20)$

$Q = 1.78 \times 10^5 J$

$Q = 169 BTU$

4 0

3 years ago

Five 60 ohm resistors are connected in parallel. What is their equivalent resistance?

Mnenie [13.5K]

Answer:

i think the answer is 12 ohms

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3 years ago

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A __________ is often written as an if/then statement. prediction law theory guess

tino4ka555 [31]

A hypothesis is often written as an if/then statement or prediction law theory guess. A hypothesis is also known as an educated guess.

Your answer is: Hypothesis

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3 years ago

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Check b and c plz :DD

Inga [223]

Both of your answers are correct

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3 years ago

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Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. You have a stopped pipe of adjustable length clo

faltersainse [42]

Answer:

Length of pipe $= 0.057$ meter

Explanation:

Speed of a transverse wave on a string

$v = \sqrt{\frac{F}{\mu} }$

where F is the tension in string and $\mu$ is the mass per unit length

Thus,

$\mu = \frac{m}{L}$

Substituting the given values we get -

$\mu = \frac{7.25 * 10^{-3}}{0.62}\\mu = 0.0117 \frac{Kg}{m}$

Speed of a transverse wave on a string

$v = \sqrt{\frac{4510}{0.0117} } \\v = 620.86 \frac{m}{s}$

For third harmonic wave , frequency is equal to

$f = \frac{nv}{2L}$

Substituting the given values, we get -

$f = \frac{3 * 620.86}{2 * 0.62} \\f = 1502.08$

Length of pipe

$L = \frac{nv}{4 f}$

Substituting the given values we get

$n = 1$ for first harmonic wave

$L = \frac{344* 1}{4*1502.08} \\L = 0.057$

Length of pipe $= 0.057$ meter

5 0

3 years ago