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2 years ago

A.

Physics

1 answer:

Brut [27]2 years ago

6 0

Answer:

$\boxed{\sf Work \ done = 4 \ J}$

Given:

Force = 8 N

Distance covered by the body = 50 cm = 0.5 m

Explanation:

Work Done = Force × Distance covered by the body

= 8 × 0.5

= 4 J

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Two astronauts of mass 100 kg are 2 m apart in outer space. What is the

fredd [130]

The force of gravity between the astronauts is $1.67\cdot 10^{-7}N$

Explanation:

The magnitude of the gravitational force between two objects is given by:

$F=G\frac{m_1 m_2}{r^2}$

where :

$G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}$ is the gravitational constant

$m_1, m_2$ are the masses of the two objects

r is the separation between them

In this problem, we have two astronauts, whose masses are:

$m_1 = 100 kg\\m_2 = 100 kg$

While the separation between the astronauts is

r = 2 m

Substituting into the equation, we can find the gravitational force between the two astronauts:

$F=\frac{(6.67\cdot 10^{-11})(100)(100)}{2^2}=1.67\cdot 10^{-7}N$

Learn more about gravitational force:

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4 0

3 years ago

Read 2 more answers

18. A person pulls horizontally with a force of 64 N on a 14-kg box. There is a force of friction between the box and the floor

MA_775_DIABLO [31]

since force=massxacceleration
therefore acceleration=force/mass
the resultant force=the acting force on the object-the frictional force
the resultant force=64-36=28N
therefore the acceleration=28/14=2m/sec^2

4 0

2 years ago

What are the (time varying) amplitudes of the E and H fields if summer sunlight has an intensity of 1150 W/m2 in any Town?

Archy [21]

Explanation:

Given that,

Intensity = 1150 W/m²

(a). We need to calculate the magnetic field

Using formula of intensity

$I=\dfrac{E^2}{2\mu_{0}c}$

$E=\sqrt{2\times I\mu_{0}c}$

Put the value into the formula

$E=\sqrt{2\times1150\times4\pi\times10^{-7}\times3\times10^{8}}$

$E=931.17\ N/C$

Using formula of magnetic field

$B = \dfrac{E}{c}$

Put the value into the formula

$B=\dfrac{931.17}{3\times10^{8}}$

$B=0.0000031039\ T$

$B=3.10\times10^{-6}\ T$

(b). The relative strength of the gravitational and solar electromagnetic pressure forces of the sun on the earth

We need to calculate the gravitational force

Using gravitational force

$F=\dfrac{Gm_{s}M_{e}}{r^2}$

Put the value into the formula

$F=\dfrac{6.67\times10^{-11}\times1.98\times10^{30}\times5.97\times10^{24}}{(1.496\times10^{11})^2}$

$F=3.522\times10^{22}\ N$

We need to calculate the radiation force

Using formula of force

$F_{R}=\dfrac{I}{c}\pi\timesR_{E}^{2}$

Put the value into the formula

$F_{R}=\dfrac{1150}{3\times10^{8}}\times\pi\times(6.378\times10^{6})^2$

$F_{R}=4.8\times10^{8}\ N$

The gravitational and solar electromagnetic pressure forces of the sun on the earth

$\dfrac{F_{G}}{F_{R}}=\dfrac{3.522\times10^{22}}{4.8\times10^{8}}$

$\dfrac{F_{G}}{F_{R}}=7.3375\times10^{13}$

Hence, This is the required solution.

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3 years ago

When heating water, during what temperature range will the temperature cease to change for some time?

Morgarella [4.7K]

Answer: Option (B) is the correct answer.

Explanation:

As we know that the temperature when the vapor pressure of liquid becomes equal to the atmospheric pressure surrounding the liquid. And, during this temperature liquid state of substance changes into vapor state.

But during this process of change in state of substance the temperature will cease to change for some time because unless and until all the liquid molecules do not convert into vapor state the temperature will not rise or change.

As the boiling point of water is $100^{o}C$ so the temperature ceases to change from $98^{o}C$ to $102^{o}C$ .

Therefore, we can conclude that when heating water, during $98^{o}C$ to $102^{o}C$ temperature range the temperature will cease to change for some time.

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3 years ago

A TV with a power rating of 267 W uses 1.9 kWh in one day. How many hours was the TV during that day?

Aleonysh [2.5K]

1.9kWh/0.267kW = 7.11 hours

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3 years ago