The car travels a distance <em>d</em> from rest with acceleration <em>a</em> after time <em>t</em> of
<em>d</em> = 1/2 <em>a</em> <em>t</em>²
It covers 69 m with 2.8 m/s² acceleration, so that
69 m = 1/2 (2.8 m/s²) <em>t</em>²
<em>t</em>² = 2 (69 m) / (2.8 m/s²)
<em>t</em> ≈ 7.02 s
where we take the positive square root because we're talking about time *after* the car begins accelerating.
Amount of matter in object is mass.density is mass/volume.h2o is water.drew first picture of atom is Neil's Bohr.l* w* h is volume.basic unit of matter is atom.mixture is concrete.n=1 is inner shell.upward force of a liquid on an object is buoyancy.
Answer:
The speed of space station floor is 49.49 m/s.
Explanation:
Given that,
Mass of astronaut = 56 kg
Radius = 250 m
We need to calculate the speed of space station floor
Using centripetal force and newton's second law
Where, v = speed of space station floor
r = radius
g = acceleration due to gravity
Put the value into the formula
Hence, The speed of space station floor is 49.49 m/s.
500 ml = 0.5 liters. that's what i'm getting
hope it helps
Answer:
A and B
Explanation:
The data sets that depict an accelerating object is Data Set A & Data Set B.
The both data sets show that the body is accelerating. Also, they show that the body started from rest (0m/s) at a 0sec.
Data Set A shows a non-constant acceleration which has changing amount of velocity with change in time. While Data Set B shows a constant acceleration which has constant amount of velocity with change in time.
