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3 years ago

12

Suppose an interdisciplinary committee of 3 faculty members is to be selected from a group consisting of 4 men and 5 women. the

probability that all three faculty selected are men is approximately _______

1 answer:

yaroslaw [1]3 years ago

6 0

you answer to the problem is 3/9

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2 years ago

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Factor this expression: 12 + 20

liberstina [14]

Answer:

<h2>12 + 20 = 4 × (3 + 5)</h2>

Step-by-step explanation:

12 = 4 × 3

20 = 4 × 5

12 + 20 = 4 × 3 + 4 × 5 = 4 × (3 + 5)

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2 years ago

Average box of crackers is 24.5 ounces with standard deviation of. 8 ounce. What percent of the boxes weigh more than 22.9 ounce

34kurt

Answer:

97.7% of of the boxes weigh more than 22.9 ounces.

15.9% of of the boxes weigh less than 23.7 ounces.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 24.5 ounces

Standard Deviation, σ = 0.8 ounce

We are given that the distribution of boxes weight is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(boxes weigh more than 22.9 ounces)

P(x > 22.9)

$P( x > 22.9) = P( z > \displaystyle\frac{22.9 - 24.5}{0.8}) = P(z > -2)$

$= 1 - P(z \leq -2)$

Calculation the value from standard normal z table, we have,

$P(x > 22.9) = 1 - 0.023 =0.977= 97.7\%$

97.7% of of the boxes weigh more than 22.9 ounces.

b) P(boxes weigh less than 23.7 ounces)

P(x < 23.7)

$P( x < 23.7) = P( z < \displaystyle\frac{23.7 - 24.5}{0.8}) = P(z < -1)$

Calculation the value from standard normal z table, we have,

$P(x < 23.7) =0.159= 15.9\%$

15.9% of of the boxes weigh less than 23.7 ounces.

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3 years ago

Find the perimeter of the figure to the nearest hundredth.

Juliette [100K]

Answer:

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Step-by-step explanation:

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2 years ago

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