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const2013 [10]
4 years ago
11

Solve 2x - 1 < 7 and 5x + 3 < 3.

Mathematics
2 answers:
sammy [17]4 years ago
8 0
For the first one:
Add 1 on each side to isolate the 2x.
2x<8
Then divide by 2 to isolate the x.
x<4

For the second one:
Subtract 3 to isolate the 5x on both sides.
5x<0
Divide by 5 to isolate the x
x<0
Nimfa-mama [501]4 years ago
3 0
1) 2x - 1 <  7
move the 1 over by addition
2x < 8
divide by 2
x < 4

2) 5x + 3 < 3
move the 3 over by subtraction
5x < 0
divide by 5
x < 0/5
x < 0
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3 years ago
How do you expand the expression 3(x+11)
Katena32 [7]
In brackets everything has to multiplied by 3. It there is no sign between its always multiply!!!

this means that it has to be

3 x X + 3 x 11

this means that we can also multyplay 3 by 11 now. 

and that equals to 33. There fore the expansion will be: 

3 x X + 33

we can also simplify 3 x X which would be 3x (as I mentioned before, It there is no sign between its always multiply!!!)

so the expansion for 3(x+11) is 3x + 33
8 0
3 years ago
The graph shows a vertical translation of y = x.
iris [78.8K]

Answer:

D is the answer

Step-by-step explanation:

3 0
3 years ago
If Julie invests $9,250 at a rate of 7%, compounded weekly, find the value of the investment after 5 years
FinnZ [79.3K]
Total = Principal * (1 + rate/n)^n*years where "n" is the number of compounding periods
Total = 9,250 * (1 + .07/52)^52*5
Total = <span>9,250 * (1.0013461538</span>)^260
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http://www.1728.org/compint3.htm


5 0
4 years ago
Estimate V55 to the nearest integer.
Tema [17]

assuming is square root of 55:

You can solve the square root and roound to the nearest number:

√55 = 7.41

Since the number after the decimal point is 4, the square root is closest to 7 than to 5.

You can also campare √55 with closest integers that are perfect square:

below 55, the closest perfect square is 49 = 7^2

above 55, the closest perfect square is 64 =8^2

55-49 = 6

64-55 = 10

Since 49 is closest to 55, it's square root is the nearest. (7)

4 0
1 year ago
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