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Nastasia [14]
3 years ago
6

(cos6x+6cos4x+15cos2x+10)/(cos5x+5cos3x+10cosx)=?

Mathematics
1 answer:
Tasya [4]3 years ago
7 0
Do you mean <span><span><span><span>cos6</span>x+6<span>cos4</span>x+15<span>cos2</span>x+10</span><span><span>cos5</span>x+5<span>cos3</span>x+10cosx</span></span>  ?</span> or <span><span><span>cos6x+6cos4x+15cos2x+10</span><span>cos5x+5cos3x+10cosx</span></span>  ?</span> or <span><span><span><span>cos6</span>x+6<span>cos4</span>x+15<span>cos2</span>x+10</span><span><span>cos5</span>x</span></span>+5<span>cos3</span>x+10cosx  ?</span> or <span><span><span>cos6x+6cos4x+15cos2x+10</span><span>cos5x</span></span>+5cos3x+10cosx  <span>?</span></span>
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Answer:

14 groups

Step-by-step explanation:

Given

Groupings = \frac{1}{2}\ day

Duration = 1\ week

Required

Determine the number of group in the week

To do this, we simply divide the duration by the number half day group.

This gives:

Group = \frac{Duration}{Groupings}

Group = \frac{1\ week}{1/2\ days}

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Group = \frac{7}{1/2}

Group = 7 / \frac{1}{2}

Convert to multiplication

Group = 7 * \frac{2}{1}

Group = \frac{14}{1}

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