The denominator can't equal 0.
![11(x-7) \not= 0 \\ x-7 \not=0 \\ x \not= 7 \\ \\ \\ \frac{(2x+1)(x-7)}{11(x-7)}=\frac{2x+1}{11} \\ \\ (2x+1)(x-7) \cdot 11= 11(x-7) \cdot (2x+1) \\ 11(2x+1)(x-7)=11(2x+1)(x-7) \\ \\ x \in R \setminus \{7 \}](https://tex.z-dn.net/?f=11%28x-7%29%20%5Cnot%3D%200%20%5C%5C%20x-7%20%5Cnot%3D0%20%5C%5C%20x%20%5Cnot%3D%207%20%5C%5C%20%5C%5C%20%5C%5C%20%5Cfrac%7B%282x%2B1%29%28x-7%29%7D%7B11%28x-7%29%7D%3D%5Cfrac%7B2x%2B1%7D%7B11%7D%20%5C%5C%20%5C%5C%0A%282x%2B1%29%28x-7%29%20%5Ccdot%2011%3D%2011%28x-7%29%20%5Ccdot%20%282x%2B1%29%20%5C%5C%0A11%282x%2B1%29%28x-7%29%3D11%282x%2B1%29%28x-7%29%20%5C%5C%20%5C%5C%0Ax%20%5Cin%20R%20%5Csetminus%20%5C%7B7%20%5C%7D)
The answer is D.
Answer:
Option B.
Step-by-step explanation:
It is given that
A = {The Rationals}
B = {The Irrationals}
We need to find the set A∪B.
If we have two sets X and Y then union of these sets (X∪Y) contains all the elements of set X, of set Y or both.
It is given that A is the set of rations and B is the set of irrational, so the union A∪B is the combined set of all rational or irrational numbers.
A∪B = {The Rationals} + {The Irrationals}
A∪B = {The Reals}
Therefore, the correct option is B.
√ (1/144) = 1/12
Because √1 = 1 ; √144 = 12
⇒ C
Answer:
y = 2x + 1
Step-by-step explanation:
1. Find the slope; (change in y values)/(change in x values)
Slope = (-5 - 3)/ (-3 - 1) = -8/-4 = 2
2. Find the y-intercept (b) using the slope intercept formula: y = mx + b
m = 2 and using point (1, 3) , solve for "b"
y = mx + b
3 = 2(1) + b
3 = 2 + b
1 = b
3. Write the linear equation: y = 2x + 1
The answer would have to be B because of the pi.