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4 years ago

If there is unequal sharing among electrons, which of the following

Physics

1 answer:

Dennis_Churaev [7]4 years ago

6 0

Answer:

D. Fluorine.

Explanation:

For an atom to accept an electron, from another atom, it must have high electron affinity compared to the other elements.

Large atoms then to have high electron affinity compared to smaller atoms and most large atoms are non metals while elements with smaller atomic radius are metals. Tin(Sn), Arsenic(As) are metals and they have lower electrons affinity compared to Sulfur (S) and Fluorine (F).

Fluorine have a high electron affinity than Sulfur and hence has a larger atomic radius and can easily draw most of the electrons shared between the two atoms.

There's a trend to electron affinity and I.e it increases down the period and decreases down the group.

Most group (VII)A elements form electrovalent compounds due to their tendency to pull the shared electron towards them(high electron affinity) compared to Sulfur (a group VIA) element.

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A proton has a speed of 3.50 Ã 105 m/s when at a point where the potential is +100 V. Later, itâs at a point where the potential

ruslelena [56]

Answer:

(a). The change in the protons electric potential is 0.639 kV.

(b). The change in the potential energy of the proton is $1.022\times10^{-16}\ J$

(c). The work done on the proton is $-8\times10^{-18}\ J$ .

Explanation:

Given that,

Speed $v= 3.50\times10^{5}\ m/s$

Initial potential V=100 V

Final potential = 150 V

(a). We need to calculate the change in the protons electric potential

Potential energy of the proton is

$U=qV=eV$

Using conservation of energy

$K_{i}+U_{i}=K_{f}+U_{f}$

$\dfrac{1}{2}mv_{i}^2+eV_{i}=\dfrac{1}{2}mv_{f}^2+eV_{f}$

$]\dfrac{1}{2}mv_{i}^2-]\dfrac{1}{2}mv_{f}^2=e(V_{f}-V_{i})$

$\dfrac{1}{2}mv_{i}^2-]\dfrac{1}{2}mv_{f}^2=e\Delta V$

$\Delta V=\dfrac{m(v_{i}^2-v_{f}^2)}{2e}$

Put the value into the formula

$\Delta V=\dfrac{1.67\times10^{-27}(3.50\times10^{5}-0)^2}{2\times1.6\times10^{-19}}$

$\Delta V=639.2=0.639\ kV$

(b). We need to calculate the change in the potential energy of the proton

Using formula of potential energy

$\Delta U=q\Delta V$

Put the value into the formula

$\Delta U=1.6\times10^{-19}\times639.2$

$\Delta U=1.022\times10^{-16}\ J$

(c). We need to calculate the work done on the proton

Using formula of work done

$\Delta U=-W$

$W=q(V_{2}-V_{1})$

$W=-1.6\times10^{-19}(150-100)$

$W=-8\times10^{-18}\ J$

Hence, (a). The change in the protons electric potential is 0.639 kV.

(b). The change in the potential energy of the proton is $1.022\times10^{-16}\ J$

(c). The work done on the proton is $-8\times10^{-18}\ J$ .

5 0

3 years ago

The kinetic energy, k, of an object varies jointly with the mass of the object and the square of the velocity of the object. a 5

o-na [289]

Answer:

KE = 1/2 M V^2 = 1/2 * 25 * 10^2 = 1250 J

Check

M2 = 1/2 M1

V2 = V1 / 2

E2 = 1/2 * 1/4 E1 = E1 / 8 = 10000 / 8 = 1250 J

8 0

2 years ago

Read 2 more answers

A 18-kg sled is being pulled along the horizontal snow-covered ground by a horizontal force of 30 N. Starting from rest, the sle

k0ka [10]

Answer:

Coefficient of kinetic friction = 0.146

Explanation:

Given:

Mass of sled (m) = 18 kg

Horizontal force (F) = 30 N

FInal speed (v) = 2 m/s

Distance (s) = 8.5 m

Find:

Coefficient of kinetic friction.

Computation:

Initial speed (u) = 0 m/s

v² - u² = 2as

2(8.5)a = 2² - 0²

a = 0.2352 m/s²

Nweton's law of :

F (net) = ma

30N - μf = 18 (0.2352)

30 - 4.2336 = μ(mg)

25.7664 = μ(18)(9.8)

μ = 0.146

Coefficient of kinetic friction = 0.146

6 0

4 years ago

What is the study of the mone and stars

maks197457 [2]

The study of the moon as well as the stars is astronomy

8 0

3 years ago

The Big Bang theory states that _____.

ohaa [14]

Answer:

the universe is expanding and will continue to expand

Explanation:

The Big Bang Theory is a theory that the universe started as an an infinitely hot and dense single point that inflated and stretched out.

8 0

3 years ago