Answer:
0.0231 m/s
Explanation:
Given the question :
A small toddler is playing in his yard. Over the course of 29.01 s, he walks 2.099 m S before turning N and walking 1.429 m. What is his average velocity?
Distance walked south = 2.099 metre
Time taken = 29.01s
Distance walked north = 1.429 metre
Average Velocity = Displacement / time
The Displacement is hence,
(2.099 m - 1.429m) = 0.67m
Average Velocity = 0.67m / 29.01s
Average Velocity = 0.02309 m/s
Average Velocity = 0.0231 m/s
The answer should be C.
Ratio it has two radioactive isotopes is compared by overtime.
Hope it helped you.
-Charlie
Answer:
d = 23.75 m
The zebra has gone 23.75m after 5 seconds.
Corrected question;
A zebra starts from rest and accelerates at 1.9 m/s2. How far has the zebra gone after 5 seconds.
Explanation:
From the equation of motion;
d = vt + 0.5at^2 .........1
Where;
d = displacement
v = initial velocity = 0
t = time taken= 5 seconds
a = acceleration = 1.9 m/s^2
Substituting the given values into equation 1;
d = 0(5) + 0.5(1.9×5^2)
d = 0.5(1.9×5^2)
d = 23.75 m
The zebra has gone 23.75m after 5 seconds.
If a football player has more mass, they will also have more <u>momentum</u>. This is because mass is directly proportional to momentum.
You use the right hand rule. With your thumb out and the rest of your fingers curved ( like a thumbs up) curve your fingers to the direction of the torque. The direction your thumbs points at is the direction of the torque
