Chemical energy.
Hope I helped :-)
Which type of mirror always has an image that is smaller than the object?
convex
They are both formed by deposited river sediment.
Answer: E = 1.93×10^-7 J
Explanation: The formulae for getting the energy stored in a capacitor is given as
E =Cv²/2
Where E = energy stored in capacitor (joules), C = capacitance of capacitor (farad), v = applied voltage =150v.
The formulae implies that we need to get the capacitance of the capacitor (C) first before we can get the energy.
From the parameters given to us
Area of plates =A = 87.5cm² = 87.5/10000 = 0.00875m²
Distance between plates = d = 4.50mm = 4.50/1000 = 0.0045m
C = ε0A/d
Where ε0 = permittivity of free space = 8.85×10^-12 F/m
C = 8.85×10^-12 × 0.00875/ 0.0045
C = 7.743×10^-14/0.0045
C = 1.72×10^-11 F.
Recall that E = Cv²/2
E = ( 1.72×10^-11 × 150×150) /2
E = 3.87×10^-7/2
E = 1.93×10^-7 J
<span>3598 seconds
The orbital period of a satellite is
u=GM
p = sqrt((4*pi/u)*a^3)
Where
p = period
u = standard gravitational parameter which is GM (gravitational constant multiplied by planet mass). This is a much better figure to use than GM because we know u to a higher level of precision than we know either G or M. After all, we can calculate it from observations of satellites. To illustrate the difference, we know GM for Mars to within 7 significant figures. However, we only know G to within 4 digits.
a = semi-major axis of orbit.
Since we haven't been given u, but instead have been given the much more inferior value of M, let's calculate u from the gravitational constant and M. So
u = 6.674x10^-11 m^3/(kg s^2) * 6.485x10^23 kg = 4.3281x10^13 m^3/s^2
The semi-major axis of the orbit is the altitude of the satellite plus the radius of the planet. So
150000 m + 3.396x10^6 m = 3.546x10^6 m
Substitute the known values into the equation for the period. So
p = sqrt((4 * pi / u) * a^3)
p = sqrt((4 * 3.14159 / 4.3281x10^13 m^3/s^2) * (3.546x10^6 m)^3)
p = sqrt((12.56636 / 4.3281x10^13 m^3/s^2) * 4.458782x10^19 m^3)
p = sqrt(2.9034357x10^-13 s^2/m^3 * 4.458782x10^19 m^3)
p = sqrt(1.2945785x10^7 s^2)
p = 3598.025212 s
Rounding to 4 significant figures, gives us 3598 seconds.</span>
