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2 years ago

Please hellllp fasttttttt

Mathematics

2 answers:

velikii [3]2 years ago

7 0

Answer:

x = 30.5

angle 1: 94 degrees

angle 2: 86 degrees

angle 3: 94 degrees

angle 4: 94 degrees

angle 5: 86 degrees

angle 6: 94 degrees

Step-by-step explanation:

DIA [1.3K]2 years ago

6 0

Answer:

Step-by-step explanation:

Because lines $m$ and $n$ are parallel, angles 1, 3, 4, 6 are equivalent, and all remaining angles are also equivalent.

Knowing this, you can set up the following equation:

$86 = 2x + 25$

$86 - 25 = 2x$

$61 = 2x$

$x = 30.5$

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HELP PLEASE !!!!!!!!!!

Arada [10]

Answer:

Answer B $(-\infty,1)U(1,2]$

Step-by-step explanation:

Notice that the quotient of f(x)/g(x) is:

$h(x)=\frac{\sqrt{2-x} }{x-1}$

therefore, this new function imposes conditions due to the fact that it has a square root in the numerator and a binomial in the denominator both with the variable x. Then, in order for the root in the numerator to be defined, the argument inside the root must be larger than or equal to zero. That is:

$2-x\geq 0\\2\geq x\\x\leq 2$

So, this condition must be satisfied by the x-values of the domain.

Then we have the binomial in the denominator, which in order to be defined needs to be different from zero. Notice that the only x-value that could cause problems (render zero) is:

$x-1=0\\x=1$

Then, $x\neq 1$

So we have to eliminate the number 1 from the previous subset that required x smaller than or equal to 2.

The way to represent this Domain is then: $(-\infty,1)U(1,2]$

8 0

2 years ago

Please help :)))) ( attachment )

Anastaziya [24]

Let,
f(x) = -2x+34
g(x) = (-x/3) - 10
h(x) = -|3x|
k(x) = (x-2)^2

This is a trial and error type of problem (aka "guess and check"). There are 24 combinations to try out for each problem, so it might take a while. It turns out that

g(h(k(f(15)))) = -6
f(k(g(h(8)))) = 2

So the order for part A should be: f, k, h, g
The order for part B should be: h, g, k f
note how I'm working from the right and moving left (working inside and moving out).

Here's proof of both claims

-----------------------------------------

Proof of Claim 1:

f(x) = -2x+34
f(15) = -2(15)+34
f(15) = 4
-----------------
k(x) = (x-2)^2
k(f(15)) = (f(15)-2)^2
k(f(15)) = (4-2)^2
k(f(15)) = 4
-----------------
h(x) = -|3x|
h(k(f(15))) = -|3*k(f(15))|
h(k(f(15))) = -|3*4|
h(k(f(15))) = -12
-----------------
g(x) = (-x/3) - 10
g(h(k(f(15))) ) = (-h(k(f(15))) /3) - 10
g(h(k(f(15))) ) = (-(-12) /3) - 10
g(h(k(f(15))) ) = -6

-----------------------------------------

Proof of Claim 2:

h(x) = -|3x|
h(8) = -|3*8|
h(8) = -24
---------------
g(x) = (-x/3) - 10
g(h(8)) = (-h(8)/3) - 10
g(h(8)) = (-(-24)/3) - 10
g(h(8)) = -2
---------------
k(x) = (x-2)^2
k(g(h(8))) = (g(h(8))-2)^2
k(g(h(8))) = (-2-2)^2
k(g(h(8))) = 16
---------------
f(x) = -2x+34
f(k(g(h(8))) ) = -2*(k(g(h(8))) )+34
f(k(g(h(8))) ) = -2*(16)+34
f(k(g(h(8))) ) = 2

5 0

3 years ago

Find the missing length <br> . Leave your answers in simplest radical form

KIM [24]

Use the Pythagorean theorem:

$x^2+7^2=14^2\\\\x^2+49=196\qquad\text{subtract 49 from both sides}\\\\x^2=147\to x=\sqrt{147}\\\\x=\sqrt{49\cdot3}\\\\x=\sqrt{49}\cdot\sqrt3\\\\\boxed{x=7\sqrt3\ mi}$