All categories

3 years ago

A rectangle measures 2 1/2 inches by 3/4 inches What is its area?

Mathematics

2 answers:

il63 [147K]3 years ago

8 0

Answer:

1 7/8

Step-by-step explanation:

I think you need to times it like 2 1/2 x 3/4, first you make 2 1/2 into 5/2 then times it like this 5/2 x 3/4. the answer is 1 7/8

Westkost [7]3 years ago

4 0

You have to do 5/2 x 3/4. The result of this is 15/8. If you simplify this it will be 1 7/8 inches

You might be interested in

A rock is released from rest and freely falls 70 m to the ground. What is its velocity just before impact? A. 1.2 m/s B. 7.0 m/s

Yuri [45]

Answer:

37.04 m/s

Step-by-step explanation:

we can use the equation x = x0 + v0t + 1/2at^2

a = -9.8 m/s^2, the acceleration due to gravity

x0 = 70 m, the starting point of x

v0 = 0 m/s

x = 0

this will allow us to solve for time

0 = 70 + 0 +-4.9t^2

t = 3.779

now we can use the equation v = v0 + at

v = 0 + 9.8(3.77)

v = 37.04 m/s

5 0

3 years ago

In the following figure, EM is tangent to circle A at point C.

Sphinxa [80]

Answer:

A must be true

Step-by-step explanation:

Since ABE and angle ACE are right angles the rest of the 2 angles are right angles either therefore EC = AB

6 0

4 years ago

Need help with Calculus 1 inverse trig functions

lidiya [134]

Answer:

$\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}$

Step-by-step explanation:

<u>The Derivative of a Function</u>

The derivative of f, also known as the instantaneous rate of change, or the slope of the tangent line to the graph of f, can be computed by the definition formula

$\displaystyle f'(x)=\lim\limits_{\Delta x \rightarrow 0}\frac{f(x+\Delta x)-f(x)}{\Delta x}$

There are tables where the derivative of all known functions are provided for an easy calculation of specific functions.

The derivative of the inverse tangent is given as

$\displaystyle (tan^{-1}u)'=\frac{u'}{1+u^2}$

Where u is a function of x as provided:

$y=3tan^{-1}(x+\sqrt{1+x^2})$

If we set

$u=(x+\sqrt{1+x^2})$

Then

$\displaystyle u'=1+\frac{2x}{2\sqrt{1+x^2}}$

$\displaystyle u'=1+\frac{x}{\sqrt{1+x^2}}$

Taking the derivative of y

$y'=3[tan^{-1}(x+\sqrt{1+x^2})]'$

Using the change of variables

$\displaystyle y'=3[tan^{-1}u]'=3\frac{u'}{1+u^2}$

$\displaystyle y'=3\frac{u'}{1+u^2}=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+(x+\sqrt{1+x^2})^2}$

Operating

$\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+x^2+2x\sqrt{1+x^2}+1+x^2}$

$\boxed{\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}}$

8 0

3 years ago

Pls Help!!<br> What is the slope of g(x) = 4x +3

soldi70 [24.7K]

Answer:

Step-by-step explanation:

Hope this helps. Please give brainliest.

3 0

3 years ago

Given a≠±b and a^2−b^2 / a+b =12, find a−b.<br> pls hlep

Readme [11.4K]

Answer:

a - b = 12

Step-by-step explanation:

Given

$\frac{a^2-b^2}{a+b}$ = 12 ← factor the numerator

a² - b² ← is a difference of squares and factors as

a² - b² = (a - b)(a + b)

Thus

$\frac{(a-b)(a+b)}{a+b}$ = 12

Cancel the common factor (a + b) on numerator/ denominator, thus

a - b = 12

7 0

3 years ago