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3 years ago

9

carmela cut a cake into 12 equal-sized pieces. She ate 2/12 of the cake and her brother ate 3/12 of the cake.What fraction of th

e cake

2 answers:

Rzqust [24]3 years ago

6 0

1/12 of the cake is left for carmela to eat

ExtremeBDS [4]3 years ago

4 0

The answer to this question is 7/12 of the cake.

Comment if you have ANY questions! Glad to help!

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What is the opsilute value for 27/90 and 100/99

belka [17]

Answer:

3 /10

Decimal Form:

0.3

Step-by-step explanation:

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3 years ago

Use the following algorithm:

andriy [413]

Answer:

First it says that you have to multiply the number x times 2, this will give you 2x as a result. Next you have to build your equation which is 2x=10, when you have an equation like this, you divide the result with the number before x (x=10÷2) your result will be x=5. Now you have to square the result (which is x) to get y, when squaring a number you have to multiply it by itself (depending of how many times it's asking to do so when there's a small number at the upper right corner of your number, that's how many times you multiply it) so if you have to square 5, it should be 5×5 which gives you the result of y being 25.

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4 years ago

dwight can drive 60 miles for each gallon of gas on his motorcycle how far can dwight go if he has 3 gallons of gas

Aleksandr-060686 [28]

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3 years ago

For positive acute angles A and B, it is known that cos A= 20/29 and tan B= 11/60. Find the value of cos(A + B) in simplest form

jek_recluse [69]

Answer:

$\displaystyle \cos(A + B) =\frac{969}{1769}$

Step-by-step explanation:

We are given that:

$\displaystyle \cos A=\frac{20}{29}\text{ and } \tan B=\frac{11}{60}$

Where A and B are positive acute angles.

And we want to find cos(A + B).

Recall that cosine is the ratio of the adjacent side to the hypotenuse. Using this information, find the opposite side with respect to Angle A:

$o=\sqrt{29^2-20^2}=21$

Tangent is the ratio of the opposite side to the adjacent side. Find the hypotenuse with respect to Angle B:

$h=\sqrt{11^2+60^2}=61$

In summary:

With respect to Angle A, the adjacent side is 20, opposite is 21, and the hypotenuse is 29.

With respect to Angle B, the adjacent side is 60, the opposite is 11, and the hypotenuse is 61.

We can rewrite our expression as:

$\displaystyle \cos(A+B)=\cos A\cos B-\sin A\sin B$

Using the above information, substitute in the appropriate values. Note that since A and B are positive acute angles, all trigonometric values will be positive. Hence:

$\displaystyle \cos(A + B)=\left(\frac{20}{29}\right)\left(\frac{60}{61}\right)-\left(\frac{21}{29}\right)\left(\frac{11}{61}\right)$

Simplify:

$\displaystyle \cos(A + B) =\frac{1200-231}{1769}=\frac{969}{1769}$

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3 years ago

When f(x) = -3, what is x?

kap26 [50]

The letter "x" is often used in algebra to mean a value that is not yet known. It is called a "variable" or sometimes an "unknown". In x + 2 = 7, x is a variable, but we can work out its value if we try!

Hope this helps

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3 years ago