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2 years ago

Qgg-jvzi-etu join this on Go*ogle meet

Mathematics

2 answers:

blsea [12.9K]2 years ago

3 0

Answer:

Step-by-step explanation:

Vitek1552 [10]2 years ago

3 0

Answer:

nahhh im good

Step-by-step explanation:

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Simplify: 3(6+6i)+i(6+6i)

GuDViN [60]

Answer:

the answer is 12+24i

6 0

3 years ago

PLS SOLVE ASAP!!!

cupoosta [38]

180 + 30x = 60 + 50x
⇒ 20x = 120
⇒ x = 6 minutes

<span>it will take 6 minutes for Millie to catch up with Ben</span>

3 0

2 years ago

Someone please help me??

lapo4ka [179]

The standard equation of a circle with centre (xc,yc) and radius R is given by

$(x-x_c)^2+(y-y_c)^2=R^2$

Substituting
centre (xc,yc) = (4,-3)
R=2.5

The equation is therefore

$(x-x_c)^2+(y-y_c)^2=R^2$
$(x-4)^2+(y-(-3))^2=2.5^2$
$(x-4)^2+(y+3)^2=2.5^2$ or
(x-4)^2+(y+3)^2=6.25

7 0

2 years ago

Write a scenario that could be represented by this equation: 3/4x = 12

Aneli [31]

Answer:

x=1 or x=16

Step-by-step explanation:

3/4x = 12 or 0.75x = 12

3/4x/3/4 = 12/3/4 or 0.75x/0.75 = 12/0.75

x=12/1 / 3/4

x= 4/4

x = 1 or x = 16

8 0

2 years ago

One day, eleven babies are born at a hospital. Assuming each baby has an equal chance of being a boy or girl, what is the probab

Andrews [41]

You only need to consider the situations where 10 or 11 of the babies are girls, then subtract those probabilities from 1. This will give probability that any other number up to 9 of the babies are girls.

Use binomial theorem.
$P(x=k) = (nCk) p^k (1-p)^{n-k}$

n = 11
k = 10,11
p = 1/2

$P(x=10) = 11 (\frac{1}{2})^{11} = \frac{11}{2048} \\ \\ P(x=11) = 1(\frac{1}{2})^{11} = \frac{1}{2048} \\ \\ P(x \leq 9) = 1 - \frac{11}{2048} - \frac{1}{2048} \\ \\ P(x \leq 9)=\frac{2036}{2048} = \frac{509}{512}$

4 0

3 years ago

Qgg-jvzi-etu join this on Go*ogle meet​

Qgg-jvzi-etu join this on Go*ogle meet