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3 years ago

Solve for x 6^(x-2)=2(3^(3x+2))

Mathematics

2 answers:

viva [34]3 years ago

4 0

Answer:

1. x = 3/2 = 1.500

2. x = ± √3 = ± 1.7321

Step-by-step explanation:

Lelechka [254]3 years ago

3 0

The vorrrect answer is 1.7

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What is the slope of a line whose equation is 5y + 6 x - 2 =0

RoseWind [281]

5y= -6x+2
5y/5 =-6x/5 +2/5
y = -1.2x +0.4

the slope is -1.2 and y intercept is 0.4

8 0

3 years ago

Read 2 more answers

How do i answer this and how do i find the modal

faltersainse [42]

So firsty up, you need to have equal denominators IN order to do this equation.

1/3 and 5/12..

3x4=12

So the rule when changing denominators, you multiply 4 intop, so it will become 4/12, and 5/12 + 4/12 = 8/12, and,

8/12 + 1/12= 9/12 and 9/12 simplified is 3/4..

So the answer is 3/4.

Hope this helped.

3 0

3 years ago

PLEASE HURRY<br> How do i solve these problems

Tatiana [17]

Answer:

X = 13

X = 70

Step-by-step explanation:

1. Since it is a right angle set the equation up as X +2 + 75 = 90.

X =13

2. Set up x - 20 + 40 = 90 since right triangles are 90 degrees

x = 70

5 0

3 years ago

Someone pls help me I'm really struggling and the assignment is almost due

Grace [21]

Answer:

x<3 and x≥5

Step-by-step explanation:

Look at the circles and what is shaded on the number line. The first circle is at x=3, and it's an open circle. An open circle means that the interval does not include that point. The arrow is going to the left, meaning x < 3.

The next circle is at x=5. It is a closed circle, so the interval does include that point (so draw a bar under the less than/greater than sign). Next, notice how the arrow is pointing to the right. That means that the blue area is at x=5 and greater than x=5, so x≥5.

5 0

3 years ago

Urn 1 contains 3 blue tokens and 2 red tokens; urn 2 contains 2 blue tokens and 4 red tokens. All tokens are indistinguishable.

Dmitry_Shevchenko [17]

Answer:

RR = 0.4

RB = 0.3

BB = 0.22

BR = 0.30

Step-by-step explanation:

P( Urn 1 ) = 2/6 = 1/3

P( Urn 2 ) = 1 - 1/3 = 2/3

Urn 1 contains : 3 blue and 2 red

P( blue | urn 1 ) = 3/5 ( with replacement ) , P( blue | urn 1 ) = 3/4 ( without replacement )

P( red | urn 1 ) = 2 / 5 ( with replacement ) , P(red | urn 1 ) = 1/2 ( without replacement )

Urn 2 contains : 2 blue and 4 red

P ( blue | urn 2 ) = 1/3 ( with replacement ) , P( blue | urn 2 ) = 2/5 ( without replacement )

P ( red | urn 2 ) = 2/3 ( with replacement) , P( red | urn 2 ) = 4/5 ( without replacement )

Determine

<u>i) Possible outcomes when two tokens are drawn from either Urn without replacement </u>

RR = [[ ( 2/5 * 1/3 ) + ( 2/3 * 2/3 ) ] * [( 1/2 * 1/3 ) + ( 4/5 * 2/3 ) ]] = 0.4

RB = [[ (2/5 * 1/3 ) + ( 2/3 * 2/3 ) ] * [ ( 3/4 *1/3 ) + ( 2/5 * 2/3 ) ]] ≈ 0.3

BB = [[ ( 3/5 * 1/3 ) + ( 1/3 * 2/3 ) ] * [ ( 3/4 *1/3 ) + ( 2/5 * 2/3 ) ]] ≈ 0.22

BR = [[ ( 3/5 * 1/3 ) + ( 1/3 * 2/3 ) ] * [ ( 1/2 * 1/3 ) + ( 4/5 * 2/3 ) ]] ≈ 0.30

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8 0

3 years ago