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3 years ago

Evaluate the expression when t = –6.4 and u = –2.8.

Mathematics

2 answers:

denis-greek [22]3 years ago

7 0

-6.4 – 4(-2.8)
-6.4 – - 11.2 = 4.8

Your answer is B: 4.8

Marrrta [24]3 years ago

4 0

The answer is -17.6.
It is -17.6 because when there is a number next to a letter you multiply.And 2.8 times 4 equals 11.2. Then you subtract it by -6.4.
so it is -6.4 - 4x2.8

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A(x-b)+bx-c=a+b, when a DOES NOT = -b ; FIND X PLEASE!!! WILL GIVE BRAINLIEST!!

tangare [24]

9514 1404 393

Answer:

x = (ab +a +b +c)/(a +b)

Step-by-step explanation:

Eliminate parentheses, subtract left terms not containing x, divide by the coefficient of x.

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2 years ago

In NC, Henderson County has a land area of about 375 square miles and Perquimans County has a land area of about 250 square mile

kirza4 [7]

375 mi^2 15

--------------- = ------ = 3/2

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At 7:00 p.m., there are 1,000 home-team fans and 700 away-team fans at a football game. After 7:00 p.m, 15 home team fans arrive

OleMash [197]

Answer:

Therefore the ratio of home-team fan to away team fan at 8:00 p.m is

=109:67

Step-by-step explanation:

Initially , total home team fans =1000

and away team fans = 700.

7:00 pm to 8:00 pm = 1 hour = 60 minutes

Given that

Every 10 minutes the number of arrival home team fans is 15.

Then in 1 minutes the number of arrival home team fans is $\frac{15}{10}$

and in 60 minutes the number of arrival home team fans is $\frac{15 \times 60}{10}$

=90

Therefore total home team fans = (90+1000)=1090

Given that

Every 10 minutes 5 fans leave of away team leave.

then in 1 minutes $\frac{5}{10}$ fans leave of away team leave.

and In 60 minutes $\frac{5\times 60}{10}$ =30 fans leave of away team leave.

Since 30 away team fans leave.

Total away team fans = (700-30)=670

Therefore the ratio of home-team fan to away team fan at 8:00 p.m is

=1090:670

=109:67

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