Jenna is correct because the square root of a rational number can still be irrational.
Take for example the square root of 2. It is an irrational number than goes 1.41421...
If you multiply just the first however many digits of the result by itself, you will never end up with a perfect 2, because the square root is irrational.
Answer:
The graph is symmetric about the origin.
The graph does not pass through the origin.
Step-by-step explanation:
We're given:
- the function y=axn
- a = 1
- n is odd
Because a = 1, then the given function can be rewritten as y = n.
The function y = n will produce a horizontal line. Any function in the form of y = a single number, such as 4 or 9.3 will produce a horizontal line.
- The graph is symmetric about the origin.
This is true, given the graph is a horizontal line.
- The graph does not pass through the origin.
This is also true. We're given that n is an odd number. The graph will only pass through the origin if n = 0, and 0 is even.
- The graph has more than one x-intercept.
This would only be true when n = 0, and this isn't possible. So, no.
The answer is g=13 I hope this helped
