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3 years ago

Indicate the formula for the following conditions. P(n,r)=

Mathematics

2 answers:

Fudgin [204]3 years ago

8 0

Answer:

n!/r!(n-r)!

The formula is the same as the combination formula except for the multiplication of r! in the denominator.

Oliga [24]3 years ago

7 0

The formula is a permutation in which n represents the sample points in the set, while r represents the number of sample points in each permutation.

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3 years ago

19) At a local river, there were 48 alligators lying on the riverbank. If of the alligators wereasleep, how many were not asleep

sergey [27]

19) 48 alligators; 7/8 of the alligators were asleep. How many were not asleep?

8/8 - 7/8 = 1/8
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4 years ago

4×0.23 what is it i don't no

kramer

4*0.23
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4 years ago

Read 2 more answers

EU (European Union) countries report that 46% of their labor force is female. The United Nations wants to determine if the perce

miss Akunina [59]

Answer:

b. We are 95% confident that between 35.5% and 44.3% of the persons in the U.S. labor force is female.

Step-by-step explanation:

1) Data given and notation

n=500 represent the random sample taken

X represent the number of females in the U.S. labor force

$\hat p=0.46$ estimated proportion of females in the U.S. labor force

$\alpha=0.05$ represent the significance level (no given, but is assumed)

z would represent the statistic

p= population proportion of females in the U.S. labor force

2) Confidence interval

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.46 - 1.96 \sqrt{\frac{0.46(1-0.46)}{500}}=0.416$

$0.46 + 2.58 \sqrt{\frac{0.46(1-0.46)}{500}}=0.504$

On this case the calculated interval is not the given , but let's assume that the confidence interval is given by the statment: "United States Department of Labor find that 95% confidence interval for the proportion of females in the U.S. labor force is .357 to .443."

3) Correct interpretation

a. The margin of error for the true percentage of females in the U.S. labor force is between 35.7% and 44.3%.

False the confidence interval not conclude about the margin of error conclude about the true proportion.

b. We are 95% confident that between 35.5% and 44.3% of the persons in the U.S. labor force is female.

True, the statement report the confidence level and the limits for the margin of error.

c. The percentage of females in the U.S. labro force is between 35.7% and 44.3%.

False, The statement is not correct because not reports the confidence level.

d. All sample of size 500 will yield a percentage of females in the U.S. labor force that falls within 35.7% and 44.3%

False the confidence interval is for the population proportion not just for the samples of size 500

e. None of these.

False, we have an option that is true.

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3 years ago