Answer:
Option B m<ZA+m<ZB = 155° is correct option.
Step-by-step explanation:
We know that sum of angles of triangle is equal to 180°
And Isosceles triangle, 2 angles are same
So, let Angle 1 = x
Angle 2 = x
Angle 3 = 130°
Finding values of angle x
x+x+130=180
2x=180-130
2x=50
x=25
So, Angle 1 = 25 °
Angle 2 = 25°
As, angle B is greater than 90°, the sum of angles added must be greater than 90°
So, Option A, C and D can't be correct, as their sum is less than 90°
Option B m<ZA+m<ZB = 155° is correct option.
Verify:
m<ZA = 25° (as found earlier)
m<ZB = 130° (given)
So, m<ZA+m<ZB = 155°
25°+130° = 155°
Perimeter=4h+4
If the base is 2 more than the height, it gives us the equation:
b=h+2
The equation for the perimeter of a rectangle can be though of as 2b+2h, so substituting in (h+2) for b from the first equation, we get 2(h+2)+2h.
This can be simplified to be 2h+4+2h or 4h+4
