Read the following statement.

If a torque of M = 300 N⋅m is applied to the flywheel, determine the force that must be developed in the hydraulic cylinder CD t

Licemer1 [7]

Answer:

Explanation:

The torque on the flywheel = 300 N-m

The force from the hydraulic cylinder will generate a moment on CA about point A.

The part of this moment that will be at point B about A must be proportional to the torque on the cylinder which is 300 N-m

we know that moment = F x d

where F is the force, and

d is the perpendicular distance from the turning point = 1 m

Equating, we have

300 = F x 1

F = 300 N this is the frictional force that stops the flywheel

From F = μN

where F is the frictional force

μ is the coefficient of static friction = 0.4

N is the normal force from the hydraulic cylinder

substituting, we have

300 = 0.4 x N

N = 300/0.4 = 750 N

This normal force calculated is perpendicular to CA. This actual force, is at 30° from the horizontal. To get the force from the hydraulic cylinder R, we use the relationship

N = R sin (90 - 30)

750 = R sin 60°

750 = 0.866R

R = 750/0.866 = <em>866.1 N</em>

3 0

3 years ago

An automobile having a mass of 1100 kg initially moves along a level highway at 120 km/h relative to the highway. It then climbs

soldier1979 [14.2K]

Answer:

$-6111.11\ \text{kJ}$

$863.28\ \text{kJ}$

Explanation:

m = Mass of automobile = 1100 kg

v = Velocity of car = 120 km/h = $\dfrac{120}{3.6}\ \text{m/s}$

h = Height of hill = 80 m

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

Change in kinetic energy

$KE=\dfrac{1}{2}m(u^2-v^2)\\\Rightarrow KE=\dfrac{1}{2}\times 1100\times (0-(\dfrac{120}{3.6})^2)\\\Rightarrow KE=-611111.11\ \text{J}$

Change in kinetic energy is $-6111.11\ \text{kJ}$

Change in potential energy is given by

$PE=mgh\\\Rightarrow PE=1100\times 9.81\times 80\\\Rightarrow PE=863280\ \text{J}$

The change in potential energy is $863.28\ \text{kJ}$ .

8 0

3 years ago

What should be the internal diameter of a glass tube if capillary rise is not exceed 2.0 mm?

prohojiy [21]

Answer:

diameter is 14.83 mm

Explanation:

given data

height = 2 mm

to find out

internal diameter

solution

we consider here material is glass and liquid is water and angle is zero if no capillary rise

we apply here capillary rise formula that is

Capillary rise h = 2T / [ r×ρ×g ] ....................1

put here r is radius and ρ = 1000 kg/m³, T = 72.7 × $10^{-3}$ N/m all value in equation 1

Capillary rise h = 2T / [ r×ρ×g ]

r = 2T / [ h×ρ×g ]

d/2 = 2T / [ h×ρ×g ]

d/2 = 2( 72.7 × $10^{-3}$ ) / [ 2× $10^{-3}$ ×1000×9.8 ]

d = 0.0148336 m

so diameter is 14.83 mm

6 0

3 years ago

Explain working mechanism of safety valve.

ValentinkaMS [17]

Answer:

Safety valves are part of the safety features placed in the system to prevent the system from experiencing over pressures

Explanation:

A safety valve is a valve that is actuated automatically when the pressure on the inlet portion rises to a specified value to allow the outflow or discharge of fluid such as liquid, steam or gas out of the system to prevent the system pressure limit from being exceeded. The design of safety valves is such that the valve closes the emergency outlet port again once the system pressure returns to normal.

5 0

3 years ago

At the end of the vowel, the soft palate (is lowered) so that the air flows out the (nasal passage). At the same time, the _____

Marat540 [252]

Answer:

At the end of the vowel, the soft palate (is lowered) so that the air flows out the (nasal passage). At the same time, the BACK of the tongue rises to articulate with the VELUM, preventing air from escaping through the MOUTH. The lips remain OPEN. The vocal folds continue to SOUND.

Explanation:

This is the way in which sound is produced in any language through the use of our organs of speech called articulators.

NOTE:

This question should be in English Category not Engineering. I believe that was an oversight from your end.

3 0

3 years ago