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prisoha [69]
3 years ago
13

For problems 1 and 2, six luminaires, similar to Style E used in the Commercial Building, are to be installed in a room that is

12 ft × 18 ft (∼3.7 m × ∼5.5 m) with a 9 ft (2.8 m) floor-to-ceiling height. The spacing ratio for the luminaire is 1:0. The maximum distance that the luminaires can be separated and achieve uniform illuminance is
Engineering
1 answer:
BlackZzzverrR [31]2 years ago
6 0

Answer:

7ft (2.13 m).

Explanation:

From the question above, the following parameters/data are given; the room dimension = 12 ft × 18 ft (∼3.7 m × ∼5.5 m), the floor-to-ceiling height = 9 ft (2.8 m) and the spacing ratio for the luminaire is 1:0.

Note that, we are not given the value or data for the height of the plane, therefore, we will make an assumption that the height of the plane = 2ft.

Hence, the work plane to luminaire distance = (9 - 2)ft = 7ft (2.13 m).

So, the maximum distance that the luminaires can be separated and achieve uniform illuminance is;

= the work plane to luminaire distance × spacing ratio for the luminaire.

= 7ft (2.13 m) × 1 = 7ft (2.13 m).

Thus, the maximum distance that the luminaires can be separated and achieve uniform illuminance is 7ft (2.13 m).

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When subject to an unknown torque, the shear stress in a 2 mm thick rectangular tube of dimension 100 mm x 200 mm was found to b
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Answer:

The shear stress will be 80 MPa

Explanation:

Here we have;

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Where;

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\tau_{ave} = \frac{T}{2tA_{m}}

Plugging in then values, gives;

\tau_{ave} = \frac{4000}{2\times 0.002 \times 0.0125} = 80,000,000 Pa

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7 0
3 years ago
Consider the velocity boundary layer profile for flow over u flat plate to be of the form u = C_1 + C_2 y. Applying appropriate
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Answer:

Explanation:

1) C program file addressOfScalar.c

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