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seraphim [82]
3 years ago
10

(a) Design a lag compensation to meet the following specifications: The step response settling time is to be less than 5 sec, th

e step response overshoot is to be less than 17%, the steadystate error to a unit-ramp input must not exceed 10%. Verify your design by plotting the step response of the compensated closed-loop system.
Engineering
1 answer:
Pavlova-9 [17]3 years ago
4 0

Answer:

Please see the attached file for the complete answer.

Explanation:

Download pdf
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The elementary liquid-phase series reaction
liraira [26]

Answer:

Concentration of A: \frac{C_{A} }{C_{Ao} } =e^{-k_{1}t }

Concentration of B: \frac{C_{B} }{C_{Ao} } =\frac{k_{1} }{k_{2}-k_{1}  } (e^{-k_{1}t } -e^{-k_{2}t } )

Concentration of C: \frac{C_{C} }{C_{Ao} } =1+\frac{k_{1} }{k_{2}-k_{1}  } e^{-k_{2}t } -\frac{k_{2} }{k_{2}-k_{1}  } e^{-k_{1} t}

the image shows the graphs of the three concentrations

Explanation:

We have the reaction:

A ------->k1--------->B------------->k2--------->C

Each reaction:

r_{A} =-k_{1} C_{A} \\r_{B} =k_{1} C_{A} -k_{2} C_{B} \\r_{C} =k_{2} C_{C}

Where Cn is the concentration of each specie (A,B,C)

The mass balance for A:

-\frac{dC_{A} }{dt} =-r_{A} \\-\frac{dC_{A} }{dt}=k_{1} C_{A} \\-\int\limits^y_x {\frac{dC_{A} }{dt} } \,=k_{1} t\\\frac{C_{A} }{C_{Ao} } =e^{-k_{1}t }

Where x=CAo and y=CA

The mass balance for B:

-\frac{dC_{B} }{dt} =-r_{B} \\-\frac{dC_{B} }{dt}=k_{2} C_{B} -k_{1} C_{A} \\\frac{dC_{B} }{dt}+k_{2} C_{B}=k_{1} C_{A}\\\frac{C_{B} }{C_{Ao} } =\frac{k_{1} }{k_{2}-k_{1}  } (e^{-k_{1}t }-ex^{-k_{2}t }  )

The mass balance for C:

\frac{C_{C} }{C_{Ao} } =1-\frac{C_{A} }{C_{Ao} } -\frac{C_{B} }{C_{Ao} } \\\frac{C_{C} }{C_{Ao} }=1+\frac{k_{1} }{k_{2}-k_{1}  } e^{-k_{2} t}-\frac{k_{2} }{k_{2}-k_{1}  }  e^{-k_{1}t }

The maximum concentration of C is:

C_{Cmax} =C_{Ao} (\frac{k_{2} }{k_{1} } )^{\frac{k_{2} }{k_{2}-k_{1}  }}  =1.6(\frac{0.01}{0.4} )^{\frac{0.01}{0.01-0.4} } =1.76mol/dm^{3}

and the maximum time is:

t_{max} =\frac{ln\frac{k_{2} }{k_{1} } }{k_{2}-k_{1}  } =\frac{ln\frac{0.01}{0.4} }{0.01-0.4} =9.4 h

6 0
3 years ago
A box of mass m = 4 kg is suspended vertically from a spring with stiffness k = 64 N/m. Determine the position of the box as a f
Hatshy [7]

Answer:

x=0.5 sin 4 t

Explanation:

Given that:

mass m = 4 kg

Stiffness K =64 N/m

Given spring mass system will be in simple harmonic motion.We know that in simple harmonic motion the natural frequency given as follows

\omega _n=\sqrt{\dfrac{K}{m}}

Now by putting the values

\omega _n=\sqrt{\dfrac{64}{4}}

\omega _n=4 rad/s

The equation of SHM given as

\ddot{x}+\omega _n^2x=0

The solution of above equation will be

x=Asin\omega _nt

x=A sin 4 t

Given at t=0 ,V= 2 m/s

So

V= 4 A cos 4 t

2 = 4 A

A= 0.5

The equation  of motion will be

x=0.5 sin 4 t

3 0
3 years ago
SMAW and GMAW use constant current arc welding machines.<br><br> True<br><br> False
Oksi-84 [34.3K]
It is true. Good luck
4 0
3 years ago
Discoloration on walls, work surfaces, ceilings, walls, and pipes may indicate a leak that is causing you to waste raw materials
suter [353]

Answer:

True :)

Explanation:

If this is a true or false question.

6 0
3 years ago
You must yield the right-of-way to all of the following EXCEPT:
Elena-2011 [213]

Answer:

You must yield the right-of-way to a police car, fire engine, ambulance, or other emergency vehicle that uses a siren and flashing lights. Pull as close to the right of the road as possible and stop until the emergency vehicle(s) has passed. However, don't stop in an intersection because that would cause a wreck.

Explanation:

please have a good day. and also mark as brainllest bye

[o]-[o]

\___/

7 0
3 years ago
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