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seraphim [82]
3 years ago
10

(a) Design a lag compensation to meet the following specifications: The step response settling time is to be less than 5 sec, th

e step response overshoot is to be less than 17%, the steadystate error to a unit-ramp input must not exceed 10%. Verify your design by plotting the step response of the compensated closed-loop system.
Engineering
1 answer:
Pavlova-9 [17]3 years ago
4 0

Answer:

Please see the attached file for the complete answer.

Explanation:

Download pdf
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A 20-mm-diameter steel bar is to be used as a torsion spring. If the torsional stress in the bar is not to exceed 110 MPa when o
ch4aika [34]

Answer:

1.887 m

Explanation:

(15 *pi)/180

= 0.2618 rad

Polar moment

= Pi*d⁴/32

= (22/7*20⁴)/32

= 15707.96

Torque on shaft

= ((22/7)*20³*110)/16

= 172857.14

= 172.8nm

Shear modulus

G = 79.3

L = Gjθ/T

= 79.3x10⁹x(1.571*10^-8)x0.2618/172.8

= 1.887 m

The length of the bar is therefore 1.887 meters

5 0
3 years ago
In order to defend against side channel power analysis, we should: ______________
wariber [46]

Answer:

Some examples of predator and prey are lion and zebra, bear and fish, and fox and rabbit. ... The words "predator" and "prey" are almost always used to mean only animals that eat animals, but the same concept also applies to plants: Bear and berry, rabbit and lettuce, grasshopper and leaf

Explanation:

8 0
3 years ago
Steam enters a turbine operating at steady state with a mass flow of 10 kg/min, a specific enthalpy of 3100 kJ/kg, and a velocit
Natali [406]

Answer:

\dot W_{out} = 133.327\,kW

Explanation:

The model for the turbine can be derived by means of the First Law of Thermodynamics:

-\dot Q_{out}-\dot W_{out} +\dot m \cdot \left[(h_{in}-h_{out})+\frac{1}{2}\cdot (v_{in}^{2}-v_{out}^{2}) + g\cdot (z_{in}-z_{out})\right] =0

The work produced by the turbine is:

\dot W_{out}=-\dot Q_{out} +\dot m \cdot \left[(h_{in}-h_{out})+\frac{1}{2}\cdot (v_{in}^{2}-v_{out}^{2}) + g\cdot (z_{in}-z_{out})\right]

The mass flow and heat transfer rates are, respectively:

\dot m = (10\frac{kg}{min})\cdot (\frac{1\,min}{60\,s} )

\dot m = 0.167\,\frac{kg}{s}

\dot Q_{out} = (0.167\,\frac{kg}{s} )\cdot (1.1\times 10^{3}\,\frac{J}{kg} )

\dot Q_{out} = 183.7\,W

Finally:

\dot W_{out} = -183.7\,W + (0.167\,\frac{kg}{s} )\cdot \left(8\times 10^{5}\,\frac{J}{kg} -562,5\,\frac{J}{kg} +29.43\,\frac{J}{kg} \right)

\dot W_{out} = 133.327\,kW

3 0
3 years ago
Why become an Android programmer?
Tpy6a [65]
As a free and open operating system, Android allows app developers to generate new ideas and work with a wide range of smartphones to open up hardware options, as companies supply a great variety of devices to choose from and high-end devices become more affordable.25 Jan 2017
4 0
3 years ago
Determine the critical load if the bottom is fixed and the top is pinned. ewew = 1. 6 ×(10)3ksi×(10)3ksi ,σyσy = 5 ksiksi
Katen [24]
<h3>What is a Critical Load?</h3>

Critical load Fcr or buckling load is the value of load that causes the phenomenon of change from stable to unstable equilibrium state.

With that beign said, first it is neessary to calculate the moment of inercia about the x-axis:

Ix= \frac{db^3}{12}\\ Ix = \frac{2.(4)^3}{12} = 10.667in

Then it is necessary to calculate the moment of inercia about the y-axis:

Iy = \frac{db^3}{12}\\ Iy = \frac{4.(2)^3}{12} = 2.662in

Comparing both moments of inercia it is possible to assume that the minimun moment of inercia is the y-axis, so the minimun moment of inercia is 2662in.

And so, it is possible to calculate the critical load:

Pc\gamma = \frac{2046\pi ^2E.I}{L^2} \\Pc\gamma= \frac{2046.\pi ^2.(1,6.10^3.10^3).2662}{(10.12)^2} \\Pc\gamma= 5983,9db

See more about critical load at: brainly.com/question/22020642

#SPJ1

4 0
2 years ago
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