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3 years ago

Solve the following equation for D. Be sure to take into account whether a letter is

Mathematics

1 answer:

Molodets [167]3 years ago

5 0

Answer: capitalized

Step-by-step explanation:

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The equation 8- 4X=0 has blank real solutions

Cloud [144]

Answer:

8-4x= 0 has only 1 solution

Step-by-step explanation:

This can only have one solution because there will only be one value that can set the equation equal to 0 that number is 2. -2 on the other hand will not work because you will get 8+8=0 which does not make sense so you can only have 1 solution.

Hope this helps

7 0

4 years ago

A bottle of soda comes in a 2-liter size. There are 29.6 mL in 1 fl oz. About how many fl oz is in 2 liters?

Alchen [17]

The answer is c because that’s how much is 2 liters

6 0

3 years ago

In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.

Tema [17]

Answer:

$Area \approx 1149\ cm^2$

Step-by-step explanation:

Given that:

ΔUVW,

Side w = 44 cm, (It is the side opposite to $\angle W$ )

Side u = 83 cm (It is the side opposite to $\angle U$ )

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

$A = \dfrac{1}{2}\times a\times b\times sinC$

Where a and b are the two sides and

$\angle C$ is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

$A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A \approx 1149\ cm^2$

So, the area of given triangle to the nearest square centimetre is:

$Area \approx 1149\ cm^2$

8 0

4 years ago

Rewrite in simplest terms: (-4x + 8y) - (-3x - 8y)

Gre4nikov [31]

Answer:

im pretty sure its − x + 16 y

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Solve 20x + 12 ≥ 14x + 30

Rashid [163]

Subtract 14x from both sides to get

$20x-14x+12 \geq 30$

Subtract 12 from both sides to get

$20x-14x \geq 30-12$

Now we have moved all terms involving x on one side, and all constant terms on the other. We can simplift both sides, i.e. sum like terms, to get

$6x \geq 18$

Now we have to divide both sides by 6. When dealing with inequality you have to be careful about dividing both sides by the same constant: if the constant is negative, the inequality side switches (i.e. $\geq \leftrightarrow \leq$ ). But this is not the case since 6 is positive, so we mantain the inequality sign:

on the other. We can simplift both sides, i.e. sum like terms, to get

$\cfrac{6x}{6} \geq \cfrac{18}{6}$

Evaluate left and right hand side:

$x \geq 3$

4 0

3 years ago