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sukhopar [10]
3 years ago
12

Please help .................

Mathematics
1 answer:
alexandr1967 [171]3 years ago
4 0
The formula to solve the area of a circle is 3.14 (pi) times the radius (1/2 of the circumference) so 3.14 x 8 = 25.12 so your answer is 25.1
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The bottom shape is a square prism with base edges of 3 cm and a height of 10 cm. What is the volume of the composite figure if
7nadin3 [17]
Answer: 96 cm^3

To answer this, start by finding the volume of the square prism. The formula is L x W x H, therefore the volume is 3 x 3 x 10 = 90.

Then, find the volume of the pyramid on the top. Use the same formula but divide it by 3 because it is a pyramid. 3 x 3 x 2 / 3 = 6

Add 90 and 6 to get 96.
6 0
3 years ago
The average price of a barrel of crude oil in a recent year was 65.37. which estimated price is incorrect.
Nutka1998 [239]

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5 0
3 years ago
Read 2 more answers
Of the entering class at a​ college, ​% attended public high​ school, ​% attended private high​ school, and ​% were home schoole
Veronika [31]

Answer:

(a) The probability that the student made the​ Dean's list is 0.1655.

(b) The probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c) The probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

Step-by-step explanation:

The complete question is:

Of the entering class at a college, 71% attended public high school, 21% attended private high school, and 8% were home schooled. Of those who attended public high school, 16% made the Dean's list, 19% of those who attended private high school made the Dean's list, and 15% of those who were home schooled made the Dean's list.

a) Find the probability that the student made the Dean's list.

b) Find the probability that the student came from a private high school, given that the student made the Dean's list.

c) Find the probability that the student was not home schooled, given that the student did not make the Dean's list.

Solution:

Denote the events as follows:

<em>A</em> = a student attended public high school

<em>B</em> = a student attended private high school

<em>C</em> = a student was home schooled

<em>D</em> = a student made the Dean's list

The provided information is as follows:

P (A) = 0.71

P (B) = 0.21

P (C) = 0.08

P (D|A) = 0.16

P (D|B) = 0.19

P (D|C) = 0.15

(a)

The law of total probability states that:

P(X)=\sum\limits_{i} P(X|Y_{i})\cdot P(Y_{i})

Compute the probability that the student made the​ Dean's list as follows:

P(D)=P(D|A)P(A)+P(D|B)P(B)+P(D|C)P(C)

         =(0.16\times 0.71)+(0.19\times 0.21)+(0.15\times 0.08)\\=0.1136+0.0399+0.012\\=0.1655

Thus, the probability that the student made the​ Dean's list is 0.1655.

(b)

Compute the probability that the student came from a private high school, given that the student made the Dean's list as follows:

P(B|D)=\frac{P(D|B)P(B)}{P(D)}

             =\frac{0.21\times 0.19}{0.1655}\\\\=0.2410876\\\\\approx 0.2411

Thus, the probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c)

Compute the probability that the student was not home schooled, given that the student did not make the Dean's list as follows:

P(C^{c}|D^{c})=1-P(C|D^{c})

               =1-\frac{P(D^{c}|C)P(C)}{P(D^{c})}\\\\=1-\frac{(1-P(D|C))\times P(C)}{1-P(D)}\\\\=1-\frac{(1-0.15)\times 0.08}{(1-0.1655)}\\\\=1-0.0815\\\\=0.9185

Thus, the probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

3 0
2 years ago
How do I get my answer
Snezhnost [94]
(h + j)(x)
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2x - 3 + -4x
-2x - 3
4 0
2 years ago
What is the distance between two points located at (–6, 2) and (–6, 8) on a coordinate plane?"
ASHA 777 [7]

Answer:

4 units

Step-by-step explanation:

X coordinate never changed so you just need to subtract 2 from 8 to see the unit difference.

3 0
3 years ago
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