Answer:
Follows are the solution to the given points:
Step-by-step explanation:
Given value:
For point a:
Moment generating function of X=?
Using formula:
integrating the values by parts:
![u = x \\\\dv = e^{(t-1)x}\\\\dx =dx \\\\v= \frac{e^{(t-1)x}}{t-1}\\\\M(t) =[\frac{e^{(t-1)x}}{t-1}]^{-\infty}_{0} -\int^{\infty}_{0} \frac{e^{(t-1)x}}{t-1} \ dx\\\\](https://tex.z-dn.net/?f=u%20%3D%20x%20%5C%5C%5C%5Cdv%20%3D%20e%5E%7B%28t-1%29x%7D%5C%5C%5C%5Cdx%20%3Ddx%20%5C%5C%5C%5Cv%3D%20%5Cfrac%7Be%5E%7B%28t-1%29x%7D%7D%7Bt-1%7D%5C%5C%5C%5CM%28t%29%20%3D%5B%5Cfrac%7Be%5E%7B%28t-1%29x%7D%7D%7Bt-1%7D%5D%5E%7B-%5Cinfty%7D_%7B0%7D%20%20-%5Cint%5E%7B%5Cinfty%7D_%7B0%7D%20%5Cfrac%7Be%5E%7B%28t-1%29x%7D%7D%7Bt-1%7D%20%5C%20dx%5C%5C%5C%5C)
![= \frac{1}{t-1} (0) - [\frac{e^{(t-1)x}}{(t-1)^2}]^{\infty}_{0}\\\\=\frac{1}{(t-1)^2}(0-1)\\\\=\frac{1}{(t-1)^2}\\\\](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B1%7D%7Bt-1%7D%20%280%29%20-%20%5B%5Cfrac%7Be%5E%7B%28t-1%29x%7D%7D%7B%28t-1%29%5E2%7D%5D%5E%7B%5Cinfty%7D_%7B0%7D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B%28t-1%29%5E2%7D%280-1%29%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B%28t-1%29%5E2%7D%5C%5C%5C%5C)
Therefore, the moment value generating by the function is 
In point b:
Using formula:
form point (a):
Differentiating the value with respect of t
when 
Use this diagram, it might help.
From the inside, whatever that layer is, it can be any of the layers outside of it.
All whole numbers
can be a rational number, but not all rational numbers
be a whole number.
Kind of like all squares can be rectangles, but not all rectangles can be a square.
The whole number has all the attributes of a rational number, but not all rational numbers have all of the attributes of a whole number.
A triangles degrees add up to 180.
well first 180-138 for angle u which is 42
then do 42+(6y-2)+(8y+14)=180
solve for y.
42+(6y-2)+(8y+14)=180
42+6y-2+8y+14=180
54+14y=180
-54 -54
14y=126
/14 /14
y=9
Answer:
2*(5x+4) + 2*(3x+2)
= 10x + 8 + 6x + 2
= 16x + 10
The perimeter of the rectangle, in feet, is represented by (16x + 10)
Midpoint formula : (x1 + x2) / 2, (y1 + y2) / 2
(2,6)...x1 = 2 and y1 = 6
(x,y)...x2 = x and y2 = y
sub
(2 + x) / 2, (6 + y) / 2 = (4,10)
(2 + x) / 2 = 4
2 + x = 4 * 2
2 + x = 8
x = 8 - 2
x = 6
(6 + y)/2 = 10
6 + y = 10 * 2
6 + y = 20
y = 20 - 6
y = 14
so ur other endpoint is (6,14) <==
