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Naddik [55]
3 years ago
10

Can whole numbers be rational numbers

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
6 0
Use this diagram, it might help.

From the inside, whatever that layer is, it can be any of the layers outside of it.

All whole numbers can be a rational number, but not all rational numbers be a whole number.

Kind of like all squares can be rectangles, but not all rectangles can be a square.

The whole number has all the attributes of a rational number, but not all rational numbers have all of the attributes of a whole number.

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Evgen [1.6K]
The answer for number one is d because 7 multiply by5 is 35
The answer for number two is a
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3 years ago
The ratio of boys to girls in a class is 4 : 5
Fofino [41]

Answer: 4/9 of the class are boys and 5/9 of the class are girls.

Step-by-step explanation:

  1. There are 9 nine students in total in the class since 4 + 5 = 9.
  2. Input the amount of boys and girls there are in the class in the numerator  and have 9 as the denominator. 4/9 of the class are boys and 5/9 of the class are girls.
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3 years ago
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Someone please help ASAP
kondor19780726 [428]

I haven't done this in a while, but I'm pretty sure the answer is D, (-3, -1.)

If you were to substitute x for -3 and y for -1 in the first inequalities and simplify, it would look like this:

-1 > -3-2

-1 > - 5

And that inequality is true, because -1 is bigger than -5. Let's also substitute in the other inequality, which would be:

-1 > 2(-3) + 2

-1 > -6 + 2

-1 > -4

And -1 is bigger than -4. So, I think the answer would be D because substituting for those values of x and y would stil. make the inequalities true.

5 0
3 years ago
Assume that the population of human body temperatures has a mean of 98.6 degrees F and a standard deviation of 0.62 degrees F. I
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Answer:

0% probability of getting a mean temperature of 98.2 degrees F or lower.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 98.6, \sigma = 0.62, n = 106, s = \frac{0.62}{\sqrt{106}} = 0.06

Find the probability of getting a mean temperature of 98.2 degrees F or lower.

This is the pvalue of Z when X = 98.2. So

Z = \frac{X - \mu}{s}

Z = \frac{98.2 - 98.6}{0.06}

Z = -6.67

Z = -6.67 has a pvalue of 0.

So there is a 0% probability of getting a mean temperature of 98.2 degrees F or lower.

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Answer:

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I'd if this is right im not smart

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