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4 years ago

What is the solution to the inequality 3t + 9 ≥ 15 ?

Mathematics

2 answers:

natulia [17]4 years ago

7 0

3t+9≥15 => 3t ≥ 6 => t ≥2 => t= [2,∞)
Hope that helps, have a nice day!! ^^

11Alexandr11 [23.1K]4 years ago

3 0

$3t+9 \geq 15 \\ 3t \geq 15-9 \\ 3t \geq 6 \ /:3 \\ t \geq 2 \\ \\ t \in[2 ; \infty \} \\ \text{Good look}$

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The table shows the amount of money Yookyung charges customers to babysit. The table represents a linear function.

suter [353]

For this case we have a function of the form:

y = mx + b

Where,

m: slope of the line

b: cutting point with the y axis.

In the context of the problem we have:

The slope of the line is the charge per hour that Yookyung charges for babysit.

The cutoff point with the y-axis is an initial fee that Yookyung charges before starting work.

The cut point with the y axis occurs when x = 0.

Therefore, observing the table we have:

b = 5

Answer:

D. Yookyung charges $5 before she begins babysitting.

3 0

3 years ago

Read 2 more answers

PLEASE PLEASE HELPPP !!

Shalnov [3]

F since its a 90-45-45

3 0

3 years ago

You have received an order of 100 robotic resistance spot welders which contains 5 defective welders. You randomly select 15 wel

erica [24]

Answer:

$P(X = 0) = h(0,100,15,5) = \frac{C_{5,0}*C_{95,15}}{C_{100,15}} = 0.4357$

$P(X = 1) = h(1,100,15,5) = \frac{C_{5,1}*C_{95,14}}{C_{100,15}} = 0.4034$

$P(X = 2) = h(2,100,15,5) = \frac{C_{5,2}*C_{95,13}}{C_{100,15}} = 0.1377$

$P(X = 3) = h(3,100,15,5) = \frac{C_{5,3}*C_{95,12}}{C_{100,15}} = 0.0216$

$P(X = 4) = h(4,100,15,5) = \frac{C_{5,4}*C_{95,11}}{C_{100,15}} = 0.0015$

$P(X = 5) = h(5,100,15,5) = \frac{C_{5,5}*C_{95,10}}{C_{100,15}} = 0.00004$

b) 0.154% probability that there are at least 4 defective welders in the sample

Step-by-step explanation:

The welders are chosen without replacement, so the hypergeometric distribution is used.

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

100 welders, so $N = 100$

Sample of 15, so $n = 15$

In total, 5 defective, so $k = 5$

(a) Determine the PMF of the number of defective welders in your sample?

There are 5 defective, so this is P(X = 0) to P(X = 5). Then

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,100,15,5) = \frac{C_{5,0}*C_{95,15}}{C_{100,15}} = 0.4357$

$P(X = 1) = h(1,100,15,5) = \frac{C_{5,1}*C_{95,14}}{C_{100,15}} = 0.4034$

$P(X = 2) = h(2,100,15,5) = \frac{C_{5,2}*C_{95,13}}{C_{100,15}} = 0.1377$

$P(X = 3) = h(3,100,15,5) = \frac{C_{5,3}*C_{95,12}}{C_{100,15}} = 0.0216$

$P(X = 4) = h(4,100,15,5) = \frac{C_{5,4}*C_{95,11}}{C_{100,15}} = 0.0015$

$P(X = 5) = h(5,100,15,5) = \frac{C_{5,5}*C_{95,10}}{C_{100,15}} = 0.00004$

(b) Determine the probability that there are at least 4 defective welders in the sample?

$P(X \geq 4) = P(X = 4) + P(X = 5) = 0.0015 + 0.00004 = 0.00154$

0.154% probability that there are at least 4 defective welders in the sample

5 0

3 years ago

Please ANSWER ASAP!!!!!!! ANSWER FIRST TO GET BRIANLIEST ANSWER!!!!!!!!

Ray Of Light [21]

Surface area
break it down
bottom and top
bottom=5 rectangle
top=2 triangles+2rectangle
areas
area of recatngle=lw
area of traignle=1/2lw

so total is
SA=(8 times 2.8)+(2.8 times 4.8) +(2.8 times 4.8)+(4.8 times 8)+(4.8 times 8)+(5 times 2.8)+(5 times 2.8)+(1/2 times 3 times 8)+(1/2 times 3 times 8)
(I'm not going to do all the math, just the result)
SA=178.08 yd^2

split the figure into 2 parts
top and bottom
bottom=rectagular prism=lwh
top=triangle tingie, wait, if we take 1/2 of it and put it with the other, half, we get a rectangular prism with 1/2 base so

bottom=8 times 2.8 times 4.8=107.52
top=1/2 times 8 times 3 times 2.8=33.6
add them
107.52+33.6=141.12 yd^3

ANSWERS
SA=178.08 yd^2
V=141.12 yd^3

4 0

3 years ago

The circumference of circle A is four times the circumference of circle B. Which statement about the areas of the circles is tru

Brums [2.3K]

Answer:

The area of circle A is 16 times the area of circle B.

Step-by-step explanation:

he area of circle A is three times the area of circle B.

It depends on the value of π.

It depends on the actual diameters of the circles.

The area of circle A is 16 times the area of circle

the circumference of a circle = 2 x pi x r

Let imagine that the radius of B is 2cm

then the circumference of B = 2 x 2 x pi = 4pi

If the circumference of a is 4 times that of B, it means the circumference is 16 and the radius is 8

Area of a circle is pi x r^2

Area of B = pi x 2^2 = 4pi

Area of A = pi x 8^2 = 64pi

64/4 = 16 pi

3 0

3 years ago