All categories

3 years ago

What is the volume of a cylinder with a radius of 3 inches and a height of 5 inches ? Rounded to the nearest tenth .

Mathematics

2 answers:

Arisa [49]3 years ago

8 0

Answer:

141.4

Step-by-step explanation:

Plug the numbers into the formula, V=πr2h, you know that your radius is 3 and your height is 5, so you get V=π(3)2(5), you just then put it in the calculator. You get 141.37, round to the nearest tenth 141.4

Viefleur [7K]3 years ago

4 0

Answer:

141.37

Step-by-step explanation:

V=π $r^{2}$ h

You might be interested in

HELP! WILL MARK BRAINLIEST WITH A EXPLANATION!!!!please & thank u

mamaluj [8]

Answer:

The answer is A

Step-by-step explanation:

8 0

3 years ago

Find the equation to the line below.

Elena L [17]

y=ax+b

->a= positive (the line is going up)

->to find a, we move one unit horizontally and look over how many units you meet the graph (1 to right, 4 up) so the a= 4

-> to find b, we look for the y-coordinate of the point where the graph and the y-axis cross. they cross in (0,1) so b is 1

when we take this all together we get y=4x+1

6 0

2 years ago

Help plss !! Will give branliest to who ever has the best answer

ozzi

Answer:

a c and e hope it helps :D

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Use any method to solve the system of equations.<br> 3x + 4y = 12<br> 2x + 3y = 10<br> Solve for y.

Scilla [17]

(x , y) = (-4 , 6) There you go

7 0

3 years ago

Use Lagrange multipliers to minimize the function subject to the following two constraints. Assume that x, y, and z are nonnegat

Rudiy27

Complete Question

The complete question is shown on the first uploaded image

Answer:

Option C is the correct option

Step-by-step explanation:

From the question we are told that

The equation is $f (x, y , z ) = x^2 +y^2 + z^2$

The constraint is $P(x, y , z) = x + y + z - 24 = 0$

Now using Lagrange multipliers we have that

$\lambda = \frac{ \delta f }{ \delta x } = 2 x$

$\lambda = \frac{ \delta f }{ \delta y } = y$

$\lambda = \frac{ \delta f }{ \delta z } = 2 z$

=> $x = \frac{ \lambda }{2}$

$y = \frac{ \lambda }{2}$

$z = \frac{ \lambda }{2}$

From the constraint we have

$\frac{\lambda }{2} + \frac{\lambda }{2} + \frac{\lambda }{2} = 24$

=> $\frac{3 \lambda }{2} = 24$

=> $\lambda = 16$

substituting for x, y, z

=> x = 8

=> y = 8

=> z = 8

Hence

$f (8, 8 , 8 ) = 8^2 +8^2 + 8^2$

$f (8, 8 , 8 ) = 192$

6 0

3 years ago