Question

Equations y1 = x2 − 5x + 8 and y2=10/x intersect at a point. What is the closest value of x when y1 = y2?

Answer 1

Answer:

C.  between 3.5 and 4

Step-by-step explanation:

We are given

$y_1=x^2-5x+8$

$y_2=\frac{10}{x}$

Since, we have to solve for x

so, firstly we will set them equal

$x^2-5x+8=\frac{10}{x}$

we can multiply both sides by x

and we get

$x^3-5x^2+8x=10$

now, we can use graphing calculator

and find intersection point between y1 and y2

so, we can see that

x=3.538 lies between 3.5 and 4

so,

C.  between 3.5 and 4