Answer:
C. solution:
3(3c-2) = 5(2c-1)
or, 9c-6 = 10c-5
or, -6+5 =<em> </em>10c-9c
or, -1 = 1c
Hence, c = -1.
D. solution:
5(5-2a) = 4(6-a)
or, 25-10a = 24 - 4a
or, 25-24 = -4a+10a
or, 1 = 6a
or, 1/6 = a
Hence, a = 1/6.
Answer:
The probability that the wait time is greater than 14 minutes is 0.4786.
Step-by-step explanation:
The random variable <em>X</em> is defined as the waiting time to be seated at a restaurant during the evening.
The average waiting time is, <em>β</em> = 19 minutes.
The random variable <em>X</em> follows an Exponential distribution with parameter
.
The probability distribution function of <em>X</em> is:

Compute the value of the event (<em>X</em> > 14) as follows:

Thus, the probability that the wait time is greater than 14 minutes is 0.4786.
The answer is -2y•(2y^4 - 3y^2 - 4y + 1)
The answer to the question is: x=3