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4 years ago

#TODO: Define a data structure to keep track of which links are part of / not part of the spanning tree.

Computers and Technology

1 answer:

RoseWind [281]4 years ago

8 0

Answer:

A spanning tree is a subset of Graph G, which has all the vertices covered with minimum possible number of edges. Hence, a spanning tree does not have cycles and it cannot be disconnected.. By this definition, we can draw a conclusion that every connected and undirected Graph G has at least one spanning tree.

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Can development and conservation of environment go hand-in-hand? Explain your point of view

Wewaii [24]

No, development and conservation of environment cannot hand in hand.

Explanation:

Because during the developmental process the destruction of the environment is necessary.For example,if you want to construct a Road which is one of the developmental activity,so to construct road the clear of forest is must .

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3 years ago

Consider the operation of deleting the root of a binary search tree. if the root has one child, then ________.

PSYCHO15rus [73]

The reference to the root of the tree should be set to null

<h3>Can the root of a binary tree be null?</h3>

Only the subtrees are nulled out, the root always remains and will never be set to null.

null-, root. -null- comes from Latin, where it has the meaning "none; not one.
'' This meaning is found in such words as: annul, null, nullify.

To learn more about it, refer

to brainly.com/question/24448358

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2 years ago

What is the minimum recommended point size for presentation text?<br> 12<br> 24<br> 36<br> 48

Darya [45]

The answer would be 24

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3 years ago

Which pickaxe in minecraft to use?

Law Incorporation [45]

Answer:

Diamond pickaxe with efficiency 3

Explanation: It will mine quicker and you can just get unbreaking

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3 years ago

Meg[] elements = {new Lois(), new Stewie(), new Meg(), new Brian()}; for (int i =0; i

Stells [14]

Complete question is attached as snapshot.

Answer:

This will result in a compilation error.

Here's the inheritance hierarchy:

Meg -> Lois -> Brian -> Stewie

Now Meg has 2 public Fxns, a() and toString().

Lois inherits from Meg and all its public functions as well but, overrides the a() fxn of its super class.

So finally Lois has fxns a(), b() and toString().

Brian extends Lois and inherits all the above listed fxns of Lois, but overrides the b() and toString() fxns.

Stewie extends Brian and inherits all the fxns of Brian, but overrides the a() and toString() fxns.

In the Main driver fxn, we call a() and b() methods of all these classes but, the base class Meg has no b() and it is not extending any class so its not available in its scope.

This results in a compilation error.

Explanation:

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3 years ago