Replace the x in x^2 + 5x - 1 by x+3:-
g(x) =
(x+3)^2 + 5(x+3) - 1
= x^2 + 6x + 9 + 5x + 15 - 1
= x^2 + 11x + 23
- thats g(x)
Answer:
The test was not statistically significant because if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 21% of the time.
Step-by-step explanation:
This is the right answer,since this result is only observed 21% of the time, so in general it's not significant, so the first 2 are eliminated. The 2 x 0.21 doesn't matter since, the percent is 21% not 42%, so it doesn't even matter. The last question we eliminate is:"The test was not statistically significant because if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 79% of the time" 79% of the time is a pretty good amount to say it's significant, but it only says 21% of the time.So, it leaves us with:The test was not statistically significant because if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 21% of the time.
Hope this helps lol (: is this a psat or somethin?
Answer:
30 inches
Step-by-step explanation:
