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Maru [420]
2 years ago
6

What occurs at one of the electrons in both an electrolytic cell and voltaic cell

Chemistry
1 answer:
max2010maxim [7]2 years ago
4 0

Answer:

In both voltaic and electrolytic cells, oxidation occurs at the anode, while reduction occurs at the cathode.

Hope this helps!

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How many moles of sulfur dioxide are in 2.26x10^33 sulfur dioxide molecules?
Alexus [3.1K]

Answer:moles = no. of molecules / Avogadro's number

          = 2.26 x 10^33 / 6.022 x 10^23

          = 3752906011

Round to significant figures which is 3 = 3.75 x 10^9 mol

Explanation:

The formula for finding how many moles of a substance when given the amount of molecules is: moles = number of molecules / Avogadro's number

3 0
3 years ago
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Answer the following questions:
Vera_Pavlovna [14]

Answer:

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4 0
2 years ago
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Please help me with this chemistry problem
Margarita [4]

Answer:

50 g of K₂CO₃ are needed

Explanation:

How many grams of K₂CO₃ are needed to make 500 g of a 10% m/m solution?

We analyse data:

500 g is the mass of the solution we want

10% m/m is a sort of concentration,  in this case means that 10 g of solute (K₂CO₃) are contained in 100 g of solution

Therefore we can solve this, by a rule of three:

In 100 g of solution we have 10 g of K₂CO₃

In 500 g of solution we may have, (500 . 10) / 100 = 50 g of K₂CO₃

6 0
3 years ago
Calculate the number of moles of carbon dioxide formed when 40.0 moles of oxygen is consumed in the burning of propane. Note the
joja [24]
The first step is to balance the equation:


<span>C3H8 + 5O2 ---> 3CO2 + 4H2O


Check the balance


element          left side        right side

C                    3                  3  
H                    8                  4*2 = 8
O                    5*2=10        3*2 + 4 = 10


Then you have the molar ratios:


3 mol C3H8 : 5 mol O2 : 3 mol CO2 : 4 mol H2O


Now you have 40 moles of O2 so you make the proportion:

40.0 mol O2 * [3 mol CO2 / 5 mol O2] = 24.0 mol CO2.


Answer: option D. 24.0 mol CO2
</span>
7 0
3 years ago
Identify and explain the process shown below. Name any two products obtained during this process and state their uses.
lapo4ka [179]

Answer:

This is heating limestone

Explanation:

Process:

limestone is heated strongly. After a while, the limestone begins to go cloudy. Test tube is heated too much that it is beginning to  soften it. After removing limewater, test tube cools down, the pressure in the test tube drops and air pressure pushes the cold the liquid into the hot test tube with terrible result.

Products:

Limestone is also known as calcium carbonate and Limewater

Click on the link provided to show the video

https://youtu.be/RLL5rT_DeKc

or search heating calcium carbonate

you will find a video

5 0
3 years ago
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