All categories

3 years ago

What occurs at one of the electrons in both an electrolytic cell and voltaic cell

Chemistry

1 answer:

max2010maxim [7]3 years ago

4 0

Answer:

In both voltaic and electrolytic cells, oxidation occurs at the anode, while reduction occurs at the cathode.

Hope this helps!

You might be interested in

How many grams of lithium hypochlorite (LiClO) are there in 0.594 moles?

Flauer [41]

Answer : The mass of lithium hypochlorite are, 34.7 grams.

Explanation : Given,

Moles of $LiClO$ = 0.594 g

Molar mass of $LiClO$ = 58.4 g/mol

Expression used :

$\text{ Mass of }LiClO=\text{ Moles of }LiClO\times \text{ Molar mass of }LiClO$

Now put all the given values in this expression, we get:

$\text{ Mass of }LiClO=(0.594moles)\times (58.4g/mole)$

$\text{ Mass of }LiClO=34.7g$

Therefore, the mass of lithium hypochlorite are, 34.7 grams.

3 0

3 years ago

The percentage of water vapor present in the air compared to that required for saturation is the ____. a. mixing ratio b. relati

Ivan

Answer:

B. Relative Humidity

7 0

3 years ago

A helium-filled balloon at 310.0 K and 1 atm, contains 0.05 g He, and has a volume of 1.21 L. It is placed in a freezer (T = 235

trapecia [35]

Answer : The value of $\Delta E$ of the gas is 2.79 Joules.

Explanation :

First we have to calculate the moles of helium.

$\text{Moles of helium}=\frac{\text{Mass of helium}}{\text{Molar mass of helium}}$

Molar mass of helium = 4 g/mole

$\text{Moles of helium}=\frac{0.05g}{4g/mole}=0.0125mole$

Now we have to calculate the heat.

Formula used :

$q=nc_p\Delta T\\\\q=nc_p(T_2-T_1)$

where,

q = heat

n = number of moles of helium gas = 0.0125 mole

$c_p$ = specific heat of helium = 20.8 J/mol.K

$T_1$ = initial temperature = 310.0 K

$T_2$ = final temperature = 235.0 K

Now put all the given values in the above formula, we get:

$q=nc_p(T_2-T_1)$

$q=(0.0125mole)\times (20.8J/mol.K)\times (235.0-310.0)K$

$q=-19.5J$

Now we have top calculate the work done.

Formula used :

$w=-p\Delta V\\\\w=-p(V_2-V_1)$

where,

w = work done

p = pressure of the gas = 1 atm

$V_1$ = initial volume = 1.21 L

$V_2$ = final volume = 0.99 L

Now put all the given values in the above formula, we get:

$w=-p(V_2-V_1)$

$w=-(1atm)\times (0.99-1.21)L$

$w=0.22L.artm=0.22\times 101.3J=22.29J$

conversion used : (1 L.atm = 101.3 J)

Now we have to calculate the value of $\Delta E$ of the gas.

$\Delta E=q+w$

$\Delta E=(-19.5J)+22.29J$

$\Delta E=2.79J$

Therefore, the value of $\Delta E$ of the gas is 2.79 Joules.

3 0

3 years ago

A.it is physical change

PIT_PIT [208]

A physical change is when something don't permanently change

5 0

3 years ago

A vial is filled with room temperature water, and blue cold water has been placed at the bottom. A warm water bag sits next to t

MrRa [10]

Explanation:

In the context, a vial which is used in store medical samples is filled with water at room temperature. And the vial is kept on a cold water. Also a water bag containing warm water is kept near the vial.

The cold water kept at the bottom of the vial is having lower kinetic energy while warm water will have higher kinetic energy than the others. Since the water in the vial is at room temperature and it is in touch with the cold blue water, the water in the vial will loose or give its temperature to the cold blue water through conduction as well as convection process since temperature always flows from a hot body towards the cold body.

On the other hand, the warm water placed next tot he vial will give its temperature to the atmosphere.

5 0

3 years ago