It is false that 1 mole of nacl(s) has a greater entropy than 1 mole of nacl (aq).
this is because nacl(aq) is in aqueous state while nacl(s) is in solid state. Nacl(aq) has greater entropy than nacl(s) because in
aqueous state their is increase in entropy. the entropy of the two ions in water has greater entropy than the solid nacl.
The ingredient's molecules would be more free and move faster, then the phase would change to liquid from solid.
<u>Explanation</u>:
- This task seeks to examine the knowledge of the kinetic phase and characteristics of matters.
- Here we see the chef described that the ingredient's molecules are moving in place – solid.
- On the advent of causing the ingredient to change phase by transferring energy into it – the ingredient's molecules would be more free and move faster, then the phase would change to liquid from solid.
Answer:
The final molarity of acetate anion in the solution is 0.0046 moles
Explanation:
The balanced equation is
Cu(C₂H₃O₂)₂ + Na₂CrO₄ = CuCrO₄ + 2Na(C₂H₃O₂)
Therefore one mole of Cu(C₂H₃O₂)₂ react with one mole of Na₂CrO₄ to form one mole of CuCrO₄ and two moles of Na(C₂H₃O₂)
Mass of copper (II) acetate present = 0.708 g
Volume of aqueous sodium present = 50 mL
Molarity of sodium chromate = 46.0 mM
Therefore
Number of moles of sodium chromate present = (50 mL/1000)×46/1000 = 0.0023 M
Number of moles of copper (II) acetate present = 181.63 g/mol
number of moles of copper (II) acetate present = (0.708 g/181.63 g/mol) =0.0039 moles
Therefore 0.0039 moles of Cu(C₂H₃O₂)₂ × (2 moles of Na(C₂H₃O₂))/1 Cu(C₂H₃O₂)₂) = 0.00779 moles of Na(C₂H₃O₂)
also 0.0023 moles of Na₂CrO₄ × (2 moles of Na(C₂H₃O₂))/1 Na₂CrO₄) = 0.0046 moles of Na(C₂H₃O₂)
Therefore the Na₂CrO₄ is the limiting reactant and 0.0046 moles of Na(C₂H₃O₂) or acetate anion is formed
<span>they are much bigger because </span><span>equilibrium constant shows ratio of </span><span>concentrations of the reactants to the equilibrium concentration of the product.</span>
