Atomic radius
Explanation:
A decrease in moving from the bottom of Group 3 to the top of the group shows an increase in trend from top to bottom.
The atomic radius of elements increases from top to bottom and decreases from the bottom to the top.
The elements in group 3 are B, Al , Ga, In and Tl
- Atomic radius is taken as half of the inter-nuclear distance between two covalently bonded atoms of non-metallic elements or half of the distance between two nuclei in the solid state of metals.
- Downs a group from top to bottom, atomic radii increases progressively due to successive shells being added.
- This compensates for the size reducing effect of the increased nuclear charge.
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<u>Answer:</u>
<em> needed to heat the amount of water giving.
</em>
<u>Explanation:</u>
To solve this question we first need to know the specific heat of water which is given by <em>4.18 joules</em> Per gram for increasing <em>1° of temperature</em>. Now since one gram of water name one joules per gram so 2 grams will need <em>twice of 4.18</em> that is 8.36 similarly 50 grams will need
Now we need to calculate the heat for 10° of change because temperature rises from 50° centigrade to 60° centigrade and difference in degrees
<em>so heat needed is= </em>
Answer: The correct answer is true.
Explanation:
There are two types of reactions based on the heat absorbed or released:
1. Exothermic reactions: In these reactions, heat is released. The energy of the products is less than the energy of the reactants. The for these reactions is negative.
2. Endothermic reactions: In these reactions, heat is absorbed by the reactants. The energy of the products is more than the energy of the reactants. The for these reactions is positive.
In the given equation:
The energy is written on the product side, which means that the heat is released in the reaction. Hence, the given equation is a exothermic reaction.
Therefore, the given statement is true.
inner core,core,outer core,mantle ,crust,water,atmosphere,
Answer : 2.31 moles of Helium was initially present in the balloon.
Explanation : Calculating the initial number of moles of helium in the balloon we need to use this method,
final moles present - 14.6 mol
Volume increased from 358.5 mL (= 0.3585 L ) to 2.26 L
<span>(14.6 mol) x (0.3585 L / 2.26 L) = 14.6 moles X 0.158 L = 2.31 moles / L</span>
<span>
</span>
<span>Hence, the initial moles was 2.31 moles/L in the helium balloon. </span>