I suspect you meant
"How many numbers between 1 and 100 (inclusive) are divisible by 10 or 7?"
• Count the multiples of 10:
⌊100/10⌋ = ⌊10⌋ = 10
• Count the multiples of 7:
⌊100/7⌋ ≈ ⌊14.2857⌋ = 14
• Count the multiples of the LCM of 7 and 10. These numbers are coprime, so LCM(7, 10) = 7•10 = 70, and
⌊100/70⌋ ≈ ⌊1.42857⌋ = 1
(where ⌊<em>x</em>⌋ denotes the "floor" of <em>x</em>, meaning the largest integer that is smaller than <em>x</em>)
Then using the inclusion/exclusion principle, there are
10 + 14 - 1 = 23
numbers in the range 1-100 that are divisible by 10 or 7. In other words, add up the multiples of both 10 and 7, then subtract the common multiples, which are multiples of the LCM.
No, without further information you can't tell which number is greater. This is because there could be any amount of other digits to the right, which changes the value of the leftmost digit depending on the number it is a part of.
Hope this helps! :)
Answer:
$175
Step-by-step explanation:
you need to specify if harriet got the 7 portion or the 5 portion. I'll answer as if she got the 7 portion.
They split it into 12 portions because the ratio is 7:5 and 7+5=12. So do $300/12=25
Assuming Maya got the 5 portion, do $25 x 5 = $125, so Maya got $125.
Assuming Harriet got the 7 portion, do $25 x 7 = $175, so Harriet got $175.
