Answer:
The minimum number of different tanks needed to safely house all the fish is:
Step-by-step explanation:
To identify the minimum number of different tanks, we're gonna concentrate in a fish species, in this case can be the A: as you see in the table, the A species can live with all the fish excepting the F and G, by their side, the F and G can't live together , by this reason, this three species must live in a different tank, in the next form:
- Tank 1: <em>A</em>
- Tank 2: <em>F</em>
- Tank 3: <em>G</em>
Now the B species, it can live with A, F and G, but for this example we can put in the tank 1 (the tank of the A species). The C especies can live with A, F and G, but how we have A and B together, we're gonna put the C especies in the tank 3 (the tank of the G especies). The D species can live with A and G, we're gonna put in the tank 1 because can live with B species too. The E species can live with A and F, we're gonna put in the tank 2 (the tank of the F species) because the E species can't live with D that is in the in the tank 1. Al last, the H species just can live with A, E, F, and H species, by this reason, the only tank that can be put is the tank 2. In this form, the order is the next:
- Tank 1: <em>A, B, D</em>.
- Tank 2: <em>F, E, H</em>.
- Tank 3: <em>G, C</em>.
And t<u>he owner of the pet store must buy three different tanks to display these tropical fish</u>.
Step-by-step explanation:
3 is the correct answer
Yo sup??
The given points are (1,1),(1,3) and (9,2)
equation of circle is
8x²+8y²+ax+by=0
let us plug in (1,1) in the equation we get
8+8+a+b=0
a+b=-16
let us now plug in (1,3) in the equation
8+8*3²+a+3b=0
a+3b=-80
let us. now solve the two equation in terms of a and b
we get
2b=--64
b=-32
and
a=-16+32
=16
therefore the equation is
8x²+8y²+16x-32y=0
Hope this helps
The ratio is 9/12 and you can write it as a proportion. so you multiply 9 by 100 then divide it by 12. answer is 75% chance
