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Valentin [98]
3 years ago
8

ATP synthase is an enzyme that helps convert ADP into ATP. Highly active ATP synthase in muscle cells directly increases which o

f the following?
Biology
1 answer:
murzikaleks [220]3 years ago
8 0

Answer: pretty sure it’s the number of mitochondria in muscle cells

Explanation:

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Usually only one season.
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Antibodies are composed of two types of peptides, heavy chains and light chains. One of the major classes of antibody molecules
timurjin [86]

Answer and Explanation:

a. form the antigen-binding site ⇒ both chains

The antigen-binding site is formed by one hypervariable region of the light chain (VL) and one hypervariable region of the heavy chain (VH). So, both type of chains contributes to antigen recognition.

b. contain multiple variable domains ⇒ none

Both chains - light and heavy - contain <u>only one</u> variable domain (VL and VH).  

c. are found in the Fab fragment ⇒ both chains

The Fab fragment is composed of portions of both light and heavy chains: each portion contains one variable domain and one constant domain. The Fab fragment binds specifically the antigen.  

d. are found in the FC fragment ⇒ heavy chains

The Fc region is composed of portions of heavy chains (CH² and CH³), so it contains constant domains.  

e. contain only one constant domain ⇒ light chains

Each light chain contains one variable domain (VL) and one constant domain (CL).  

f. contain multiple constant domains ⇒ heavy chains

Each heavy chain contains three constant domains: CH¹, CH² and CH³.  

g. contain only one variable domain ⇒ both chains

Both light and heavy chains contain one variable domain. The difference is given by the number of constant domains: light chains have 1 constant domain while heavy chains have 3 constant domains.

8 0
3 years ago
What characteristic do all Imperfect Fungi have in common?
Olenka [21]
The answer is b) "No known sexual mode of spore formation
6 0
3 years ago
Which of the following is a
Levart [38]
B Hope this helped!!
8 0
3 years ago
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if the velocity of a vehicle starting from rest reaches 5m/2s in 2seconds, is the velocity of the vehicle uniform ?explain.​
Vanyuwa [196]

Explanation:

Avg speed × total times = total distance

20×25=500

Since acceleration in the 1st interval is same as deceleration in the 3rd interval and deceleration is from the same velocity achieved after acceleration, t

1

=t

3

s

1

=

2

1

×5t

1

2

s

2

=(5t

1

)t

2

s

3

=(5t

1

)×t

3

−

2

1

×5×t

1

2

=(5t

1

)×t

1

−

2

1

×5×t

1

2

s

1

+s

2

+s

3

=5t

1

t

2

+5t

1

2

⇒5t

1

2

+5t

1

t

2

=500−−−−1

2t

1

+t

2

=25−−−−2

Solving (1 ) and (2) ⇒t

1

=5,t

2

=15sec

6 0
3 years ago
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