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2 years ago

ASAP plizzzz I need help it's soooooo confusing

Mathematics

1 answer:

saul85 [17]2 years ago

6 0

Which one question did you want us to answer? all?

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What is the sum of the first 10 terms of the sequence defined by an=3n-3?

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The answer is D. 135

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Please help this is on one of my finals <br> Find the sum <br> 8/14 + 7/14 + 2/14

mylen [45]

The answer would be 1 3/14

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2 years ago

The length of the race on sunday was 2 km. what is the length of 4 of those same races in meters?

muminat

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4*2000=8000

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A bank's loan officer rates applicants for credit. The ratings are normally distributed with a mean of 200 and a standard deviat

Alika [10]

Answer:

$P(170$

And we can find the probability with this difference:

$P(-0.6$

And using the normal standard table or excel we got:

$P(-0.6$

And the best answer would be:

0.3811

Step-by-step explanation:

Let X the random variable that represent the ratings of a population, and for this case we know the distribution for X is given by:

$X \sim N(200,50)$

Where $\mu=200$ and $\sigma=50$

We are interested on this probability

$P(170$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

Using the z score we got:

$P(170$

And we can find the probability with this difference:

$P(-0.6$

And using the normal standard table or excel we got:

$P(-0.6$

And the best answer would be:

0.3811

6 0

2 years ago

[20points][Precal] Find the cross product of -(3/4)V and (1/2)w if v = <-2, 12, -3> and w = <-7, 4, -6>

Lana71 [14]

$\mathbf v=\langle-2,12,-3\rangle=-2\,\vec i+12\,\vec j-3\,\vec k$
$-\dfrac34\mathbf v=\dfrac32\,\vec i-9\,\vec j+\dfrac94\,\vec k$

$\mathbf w=\langle-7,4,-6\rangle=-7\,\vec i+4\,\vec j-6\,\vec k$
$\dfrac12\mathbf w=-\dfrac72\,\vec i+2\,\vec j-3\,\vec k$

$-\dfrac34\mathbf v\times\dfrac12\mathbf w=\begin{vmatrix}\vec i&\vec j&\vec k\\\frac32&-9&\frac94\\-\frac72&2&-3\end{vmatrix}$
$=\left((-9)\times(-3)-\dfrac94\times2\right)\,\vec i-\left(\dfrac32\times(-3)-\dfrac94\times\left(-\dfrac72\right)\right)\,\vec j+\left(\dfrac32\times2-(-9)\times\left(-\dfrac72\right)\right)\,\vec k$
$=\dfrac{45}2\,\vec i-\dfrac{27}8\,\vec j-\dfrac{57}2\,\vec k=\left\langle\dfrac{45}2,-\dfrac{27}8,-\dfrac{57}2\right\rangle$

6 0

2 years ago