Answer: <span>Based on giveninformation, the compound is a
<u>Poly Unsaturated</u> fatty acid.
Explanation: Fatty acids are carboxylic acids with -COOH functional group and a chain of hydrocarbons.
Fatty Acids are classified as,
i) Saturated Fatty Acids: Those Fatty Acids in which there is no double bond between the carbon chain are called as saturated fatty acids.
Examples: Lauric Acid </span>CH₃(CH₂)₁₀COOH<span>
Myristic Acid </span>CH₃(CH₂)₁₂COOH<span>
Palmitic Acid </span>CH₃(CH₂)₁₄COOH
ii) Unsaturated Fatty Acids: Those Fatty Acids in which contain a single double bond (mono-unsaturated) or more than one double bond (poly-unsaturated) d between the carbon atoms in a chain are called as unsaturated fatty acids.
Examples: <span>
Linoleic acid</span>
<span>
Vaccenic acid </span><span>
Palmitoleic acid
The saturated fatty acid containing 26 carbon atoms is called as
Cerotic acid. While cerotic acid containing a double bond at position 3 and 9 has a IUPAC name
H</span>
exacosa-3,9-dienoic acid with following structure.
Answer:-
KOH determines how much Mg(OH)2 is made.
2 mol of Mg(OH)2 formed
Explanation:-
The balanced equation is
MgCl2 + 2KOH --> Mg(OH)2+ 2KCI,
From seeing the coefficients we notice
2 mol of KOH reacts with 1 mol of MgCl2
4 mol of KOH reacts with 1 x 4 / 2 = 2 mol of MgCl2
3 moles of MgCl2 was added but only 2 mol react.
So we see there is excess MgCl2 .
Hence KOH is the limiting reactant.
So KOH determines how much Mg(OH)2 is made.
We see from the balanced chemical equation,
2 mol of KOH gives 1 mol of Mg(OH)2.
4 mol of KOH will give 1 x 4 /2 = 2 mol of Mg(OH)2.
Ionic bond is the bond that creates a crystalline structure
Yes it is just in the back which still makes it negative